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2 years ago

How do the models below and in problem 5 show that -6- (-5) is the same as -6 + 5?

Mathematics

1 answer:

prisoha [69]2 years ago

4 0

Answer:

it shows that a negitive and positive get rid of each other like 1+(-1)=0

so it shows that if you take -5 away from -6 your geting rid of 5 so -1

Hope This Helps!!!

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A rectangle has a length of 34 inches less than 5 times it’s width. If the area of the rectangle is 867 square inches, find the

pshichka [43]

Length of the rectangle is 51 inches

<u>Solution:</u>

Given that

Length of the rectangle in 34 miles less than 5 times its width

Area of rectangle = 867 square inches

Need to determine length of the rectangle.

Let assume width of the rectangle be represented by variable x.

So 5 times width of the rectangle =5x

34 inches less than 5 times width of the rectangle = 5x – 34

As Length of the rectangle in 34 miles less than 5 times its width

=> Length of the rectangle = 5x – 34

<em><u>The formula for rectangle is given as:</u></em>

$\text { area of rectangle }=length \times width$

As given that Area of rectangle = 867 square inches

$\begin{array}{l}{=>867=(5 x-34) \times(x)} \\\\ {=>5 x^{2}-34 x-867=0}\end{array}$

On solving quadratic equation by using quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case a = 5, b = -34 and c = -867

On substituting value of a, b and c in quadratic formula we get

$\begin{array}{l}{x=\frac{-(-34) \pm \sqrt{(-34)^{2}-4 \times 5 \times(-867)}}{2 \times 5}} \\\\ {=>x=\frac{34 \pm \sqrt{18496}}{10}=\frac{34+136}{10}} \\\\ {=>x=\frac{34+136}{10}=17 \text { or } x=\frac{34-136}{10}=-10.2}\end{array}$

Since x represents width, it cannot be negative, so x = 17

Length of the rectangle = 5x – 34 = 5(17) – 34 = 51

Hence length of the rectangle is 51 inches

5 0

3 years ago

PLEASE HELP QUICK, I need to know the answer.

Marysya12 [62]

The equivalent expression is $7^{2}$ .

We have the following expression -

$\frac{7^{-3} }{7^{-5} }$

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

$f(x, y) =\frac{A^{x} }{A^{y} }$

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = $A^{x} A^{-y} = A^{x-y}$

In the question given we have -

$\frac{7^{-3} }{7^{-5} }$

Using the property discussed above -

$7^{-3}\;7^{5}$ = $7^{-3+5}$ = $7^{2}$

Hence, the equivalent expression is $7^{2}$ .

To solve more questions on exponents, visit the link below -

brainly.com/question/17173276

#SPJ5

3 0

2 years ago

Read 2 more answers

Please help ASAP!!!!

kenny6666 [7]

The answer is letter b

4 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP MMMMMMMMMMMMMMMMEEEEEEEEEEEEEEEE

Fudgin [204]

Y=2x+1 I think this is correct but I don’t know how to do equations very well

3 0

3 years ago

Can someone please please help me on this algebra problem I’m stuck on answering the question?

Rudik [331]

Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

$\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}$

Answer: Midline=1

1) Amplitude

$\text{Amplitude =}2$

2) Periods

$\begin{gathered} \text{Period}=6 \\ \Rightarrow b=\frac{2\pi}{6} \end{gathered}$

4) The trigonometric equation is,

$\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}$

Answer:

$y=2\cos (\frac{2\pi}{6}x)+1$

4 0

1 year ago