Question

The first astronaut on mars tossed a rock straight up.the height h measured in feet after tt seconds is given by function h(t)=-6t²+24t+6
After how many seconds will the rock be 30 ft above the surface of Mars?

After how many seconds will the rock be 10 ft above the surfaces of Mars? (Round to nearest hundredth)


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Answer 1

Answer:

h'(t)= -12

Step-by-step explanation:

h'(t)=d/dt (-6t x 2 + 24 + 6)

h'(t)=d/dt (-12t + 24 + 6)

h'(t)=d/dt (-12t + 30)

h'(t)=d/dt (-12t) + d/dt (30)

h'(t)= -12+0