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kumpel [21]
3 years ago
6

What is the value of x in the equation One-third x minus two-thirds = negative 18? –56 –52 52 56What is the value of x in the eq

uation One-third x minus two-thirds = negative 1What is the value of x in the equation One-third x minus two-thirds = negative 18? –56 –52 52 568? –56 –52 52 56
Mathematics
2 answers:
maks197457 [2]3 years ago
7 0

Answer:

-52!

Hope I helped! :}

AleksAgata [21]3 years ago
5 0

Answer:

  –52

Step-by-step explanation:

Clear the fractions, then add 2.

  \dfrac{1}{3}x-\dfrac{2}{3}=-18\\\\x-2=-54\qquad\text{multiply by 3}\\\\\boxed{x=-52}\qquad\text{add 2}

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Five less than four times a number is nine more than twice a number
Leokris [45]
5-4a=9+2a
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The city of Houston received 8 more inches of rain than the town of Groesbeck. Which algebraic expression represents the amount
Ivahew [28]

Answer:

8-i=g

Step-by-step explanation:

g= amount of rain Groesbeck gout

i = inches of rain

8 0
2 years ago
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Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
3 years ago
Answer the Question below (45 points)
iren [92.7K]

3x-5=-6x+13 : Given

3x=-6x+18 : Addition property of Equality

9x=18: Subtraction property of Equality

x=2: Division Property of Equality

Step-by-step explanation:

We need to give justification to each step

Step 1:

3x-5=-6x+13

This is the question given, which we need to solve and find value of x.

Justification: Given

Step 2:

Adding 5 on both sides of the equation using addition property of equality.

3x-5+5=-6x+13+5

Simplifying

3x=-6x+18

Justification: Addition property of Equality

Step 3:

Adding 6x on both sides of the equation

3x+6x=-6x+18+6x

9x=18

Justification: Subtraction property of Equality

Step 4:

Divide both sides of the equation by 9, to find the value of x using division property of equality

9x/9=18/9

x=2

Justification: Division Property of Equality

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

8 0
3 years ago
Help please! Will mark you as Brainliest!
shutvik [7]

Answer:

21

Step-by-step explanation:

5 0
2 years ago
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