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2 years ago

Hello in need of a math question answer for a test.

Mathematics

1 answer:

creativ13 [48]2 years ago

7 0

Answer:

There are no roots

Step-by-step explanation:

The Roots are:- x-values for which the function equals zero

and this function doesn't intersect with x-axis (There are no X-values that we can plot into this function and get zero as output)

which mean there are no root for this function

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If f(x) = 3x2 + 1 and g(x) = 1 – x, what is the value of (f – g)(

alekssr [168]

(f - g)(x) = (3x² + 1) - (1 - x)
= 3x² - x
OR
= x(3x - 1)

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3 years ago

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Oleta has five times as many pennies as quarters. Altogether she has $1.80 how many of each coin does she have

Vaselesa [24]

She has 45 pennies and 9 quarters

5:1

P:Q

0.01:0.15

0.05:0.15 0.1:0.3 0.15:0.45 0.2:0.6 0.25:0.75 0.3:0.9 0.35:1.05 0.4:1.2
0.45:1.35

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3 years ago

Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system. [Start 2 By 3 Matrix 1s

Leni [432]

Answer: h = 9

Step-by-step explanation: A system of linear equations is consistent when it has at least one solution.

The matrix given is:

$\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right]$

Transform this matrix in a row-echelon form:

$\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right]$ $R_{2} = 3R_{2}+R_{1}$ $\left[\begin{array}{ccc}-15&21&h\\0&0&-9+h\end{array}\right]$

For this row-echelon form to have solutions:

-9 + h = 0

h = 9

For this system to be consistent: h = 9.

3 0

3 years ago

Powers of products and quotients. simplify (7y^4)^2

Semenov [28]

The answer simplified is 49y^8

5 0

3 years ago

Find the surface area no links no pdfs just type it into the answer section will give brainliest

rewona [7]

Check the picture below.

let's firstly convert the mixed fractions to improper fractions.

$\stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} ~\hfill \stackrel{mixed}{12\frac{1}{2}}\implies \cfrac{12\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{25}{2}} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{\Large Areas}}{\stackrel{two~triangles}{2\left[ \cfrac{1}{2}\left(\cfrac{15}{2} \right)(10) \right]}~~ + ~~\stackrel{\textit{three rectangles}}{(10)(15)~~ + ~~\left( \cfrac{15}{2} \right)(15)~~ + ~~\left( \cfrac{25}{2} \right)(15)}} \\\\\\ 75~~ + ~~150~~ + ~~112.5~~ + ~~187.5\implies \boxed{525}$

8 0

2 years ago