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Lubov Fominskaja [6]

2 years ago

9

Which choice is similar to the figure shown?

1 answer:

babunello [35]2 years ago

4 0

First choice in the upper left corner.

It is the same shape with same proportions, just dilated.
2/5 = 0.4
8/20 = 0.4

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Twelve more than two times a number is 32

anastassius [24]

Answer: 76

Step-by-step explanation:

32x2=64

64+12

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3 years ago

Tom has a water tank that holds 5 gallons of water.Tom uses water from a full tank to fill 6 bottles that each hold 16 ounces an

Shtirlitz [24]

1 gallon is 128 ounces, 5 gallons is 640 ounces. So 6*16=94 ounces Pitcher equals 64 ounces, so 640-158=452, there are 452 ounces of water left

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3 years ago

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Jan completes 60 trials of pulling colored marbles out of a bag. She pulled green 15 times. If there are 250 marbles in the bag,

Vilka [71]

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the answer is 63 green marbles

Step-by-step explanation:

8 0

3 years ago

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Need help with this. Show your steps so I could check my work and my answer.

andrezito [222]

Answer:

25

Step-by-step explanation:

The angle at C is 90 degrees, and BCD is a right triangle, so we can applythe Pythagorean theorem here -- 60²+m²=65², so 65²-60²=m²=625. The possible values for m are 25 and -25, and since m can't be negative, 25 is our answer as 25 is the square root of 625

8 0

4 years ago

A conical paper funnel of radius 4 and height 6 units is needed to make a good cup of coffee. If this funnel is made out of a se

Nimfa-mama [501]

Answer:

The radius of this circle is $2\sqrt{13}$ and the central angle of the sector is $\theta=\frac{2}{\sqrt{13}}\times360^\circ$ .

Step-by-step explanation:

Consider the provided information.

If a conical paper funnel is made out of a sector of circle then the radius of the sector becomes the slant height of the cone, and the length of the curved part of the sector becomes the circumference of the base of the cone.

First find the slant height: $l=\sqrt{r^2+h^2}$

$l=\sqrt{4^2+6^2}$

$l=\sqrt{16+36}$

$l=2\sqrt{13}$

Thus, the radius of the sector is $2\sqrt{13}$ which is same as the slant height of the cone.

Now, the circumference of the base of the cone is same as the length of the curved part.

$C=2\pi r$

$C=2\pi \times4=8\pi$

The length of the curved part = $\frac{\theta}{360\circ}\times2\pi r$

$\frac{\theta}{360\circ}\times2\pi \times2\sqrt{13}=8\pi$

$\frac{\theta}{360\circ}\times\sqrt{13}=2$

$\theta=\frac{2}{\sqrt{13}}\times360^\circ$

Hence, the radius of this circle is $2\sqrt{13}$ and the central angle of the sector is $\theta=\frac{2}{\sqrt{13}}\times360^\circ$ .

4 0

4 years ago