I dont understand life, for example, look at my username.
Answer:
heat energy is released into the surrounding
A
Explanation:
Weather can be defined as the day-to-day changes in the atmospheric parameters like temperatures, humidity, rainfall, and pressure. When these weather changes are observed for approximately over 30 years, the climate of the regions can be determined by understanding the patterns.
Answer:
88,88 % de O y 11,11 % de H
Explanation:
La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:
<em>Masa molar agua:</em>
2H = 2*1g/mol = 2g/mol
1O = 1*16g/mol = 16g/mol
Masa molar = 2 + 16 = 18g/mol
100g H2O * (1mol / 18g) = 5.556 moles H2O.
Moles de hidrógeno:
5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H
Moles Oxígeno = Moles H2O = 5.556 moles
La masa de hidrógeno es:
11.11mol * (1g/mol) 11.11g H
La masa de oxígeno es:
5.556 mol * (16g / 1mol) = 88.89g O
Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:
<h3>88,88 % de O y 11,11 % de H</h3>
Answer : The average atomic mass of chlorine is, 32.37 amu
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
As we are given that,
Mass of isotope 1 = 34.97 amu
Percentage abundance of isotope 1 = 75.77 %
Fractional abundance of isotope 1 = 0.7577
Mass of isotope 2 = 36.97 amu
Percentage abundance of isotope 2 = 24.23 %
Fractional abundance of isotope 2 = 0.2423
Now put all the given values in above formula, we get:
![\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5Csum%5B%2834.97%5Ctimes%200.7577%29%2B%2824.23%5Ctimes%200.2423%29%5D)
Therefore, the average atomic mass of chlorine is, 32.37 amu
