The graph of the function has slope of 1 and y-intercept of -6.
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The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12
<em><u>Solution:</u></em>
Let "a" be the price of each senior ticket
Let "b" be the price of each child ticket
<em><u>On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68</u></em>
Thus a equation is framed as:
4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68
4a + 4b = 68 ---------- eqn 1
<em><u>The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets</u></em>
Similarly, we frame a equation as:
12a + 5b = 120 ---------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 3</u></em>
12a + 12b = 204 -------- eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
12a + 12b = 204
12a + 5b = 120
( - ) --------------
7b = 84
b = 12
<em><u>Substitute b = 12 in eqn 1</u></em>
4a + 4(12) = 68
4a + 48 = 68
4a = 20
a = 5
Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12
Answer:
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Working together, Sam and Charlie can change all light bulbs in the office building in 3 hours. It would have taken Charlie 8 hours to do the job alone. Which equation can be be used to solve for the rate 'r', for Sam to change all the light bulbs in the office building by himself.
Let Sam can change the bulbs in the office alone in 'r' hours
Per hour work done by Sam alone =
Let Sam takes he time to change the same bulbs in the office alone = 8 hours
Per hour work done by Sam =
Since, Sam and Charlie complete the work together in time = 3 hours
Therefore, per hour work done by both =
Equation for per work done by both will be,
Per hour work done by both = Per hour work done by Sam alone + Per hour work done by Charlie
Therefore, equation for the rate 'r' will be,