All categories

2 years ago

4) The triangle on the right is an equilateral Find the value of X and Y

Mathematics

1 answer:

ozzi2 years ago

7 0

Answer:

angle Y is 29 degrees

angle X is 120 degrees

Step-by-step explanation:

Well, if the triangle is an equilateral, then all the angles are equal to

60 degrees

that means the the angle at the top point is 60+31 = 91 degrees

the right point is 60 degrees

every triangle has 180 degrees total

180 - (91+60) = 29 degrees

NOW FORGET ABOUT THE EQUILATERAL FOR A BIT

180 = 31+x+29

simplify

180 = 60+x

subtract 60 from both sides

120 = x

You might be interested in

1. Amanda weighs 48 pounds (lbs). The physician ordered a drug that is delivered in the proportion of milligrams (mg) of medicat

allsm [11]

48 pounds/1 * 1 kg/2.2 pounds=21.82 kg
amanda weighs 21.82 kg, so the amount of medication that needs to be administered should be 21.82 mg.

4 0

3 years ago

What is likely to be the subject of a direct geometric proof?

Murrr4er [49]

Theorem. .......aaaa

6 0

2 years ago

Read 2 more answers

What is the y-intercept of the line whose equation is y=1/2x-3

Aleksandr [31]

Answer:

-3

Step-by-step explanation:

y=mx+b

3 0

3 years ago

The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon

Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

$x(1)=0.11$

b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

4 0

3 years ago

How do i solve 2x-y=9

devlian [24]

20 with a number minus what will equal 9. ^_^

3 0

3 years ago