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3 years ago

4) The triangle on the right is an equilateral Find the value of X and Y

Mathematics

1 answer:

ozzi3 years ago

7 0

Answer:

<em>angle Y is 29 degrees</em>

<em>angle X is 120 degrees</em>

Step-by-step explanation:

Well, if the triangle is an equilateral, then all the angles are equal to

60 degrees

that means the the angle at the top point is 60+31 = 91 degrees

the right point is 60 degrees

every triangle has 180 degrees total

180 - (91+60) = 29 degrees

NOW FORGET ABOUT THE EQUILATERAL FOR A BIT

180 = 31+x+29

simplify

180 = 60+x

subtract 60 from both sides

120 = x

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Which values of X are solutions to the inequality

Natasha_Volkova [10]

Answer:

The third answer choice

Step-by-step explanation:

-3(x+2) < 5x+10

-3x-6 < 5x+10

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-8x < 16

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3 years ago

Which expression is equivalent to -5(-2k+4)

Wittaler [7]

If you distribute -5 to the things in the parenthesis you would get 10k-20 which is the same as -5(-2k+4)

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3 years ago

Convert the following repeating decimal to a fraction in simplest form .31 with the 1 repeating

bekas [8.4K]

Answer:

14/45

Step-by-step explanation:

So we have the fraction:

$0.3\bar1=0.31111...$

We can do this algebraically. Follow to following steps:

Let's let this number equal to n. Thus:

$0.31111...=n$

Since there is only 1 digit repeating, let's multiply everything by 10. So:

$3.1111...=10n$

Now, subtract n from both sides:

$3.1111-n=10n-n$

On the left, substitute the number for n. On the right, combine like terms:

$3.1111...-0.31111...=9n$

All of the 1s will cancel. So:

$3.1-0.3=9n$

Subtract:

$2.8=9n$

Divide both sides by 9:

$n=2.8/9$

Remove the decimal by multiplying both sides by 10:

$n=28/90$

Reduce:

$n=14/45$

And we're done!

Use a calculator to check:

$14/45\stackrel{\checkmark}{=}0.31111...$

7 0

3 years ago

I need help with this question. Thanks

masha68 [24]

Answer:

Step-by-step explanation:

4 0

4 years ago

A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o

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$\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx$

which is more readily computed in cylindrical coordinates as

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}$

7 0

3 years ago