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Oksi-84 [34.3K]
2 years ago
10

Use the following table to answer the question below.

Mathematics
1 answer:
MrMuchimi2 years ago
3 0

Answer:

It might be positive I think?

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Determine the intervals on which the function is increasing, decreasing, and constant. (5 points)
TEA [102]
The one above the one you have now
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3 years ago
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10x is greater than or equal to 120 cm^2
Agata [3.3K]

Answer:

x greater than or equal to 12cm^2

Step-by-step explanation:

8 0
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Find p if 45 :72=72 40:p​
leonid [27]
Here

45 :72 = 40:p
Or 45/72=40/p
Or 45p = 72*40

Or p = 2880/45

Or p= 64

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Ayanas
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2 years ago
What is the solution of 3x + y = 9 and 3x − 5y = 15?
Alinara [238K]
3x+y=9 ....(1)
3x-5y=15. ......(2)
-[3x-5y=15]
=> 3x+ y = 9
-3x+5y=-15
..........................
0 +6y=-6
so,y=-1
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4 0
3 years ago
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Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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