1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksju [112]
2 years ago
7

Clayton drove at a constant rate on the highway for a trip to the beach. He did not make any stops along the way. The distance C

layton had driven at any given time describes a linear function. At 3:00 p.m., he had driven 90 miles. At 4:30 p.m., he had driven 180 miles. Which statement about Clayton’s trip is true?
1.Clayton started driving at 1:30 p.m., and he drove 60 miles per hour.


2.Clayton started driving at 3:00 p.m., and he drove 60 miles per hour.



3.Clayton started driving at 1:30 p.m., and he drove 90 miles per hour.


4.Clayton started driving at 4:30 p.m., and he drove 90 miles per hour.
Mathematics
1 answer:
Nikolay [14]2 years ago
3 0

The answer is the first 1 !!

Here is how we see if it is true!

If Clayton drives 60 miles per hour, that means, <u>t</u>hat after one hour has passed, they should have traveled 60 miles!

If we look at the number of hours that have passed between 1:30 and 4:30, it is 3 hours.

If someone travels 60 miles every hour that has passed, and they traveled for 3 hours. To find how far they have traveled we just need to multiply 60 miles by 3 hours!

Let's solve that!

60 × 3 = 180 miles!

Clayton started driving at 1:30 pm and went 60 miles per hour.

You might be interested in
SOMEONE PLZ HELP SO I CAN NOT GET A 10% again :) thanks I will let u hit my cart
Step2247 [10]

Answer:

it's "c" or the third option

4 0
3 years ago
Suppose your friend's parents invest $20000 in an account paying 7% compounded annually. What will the balance be in 7 years
Greeley [361]
The balance will be: <span>$500,637.91



</span>
3 0
3 years ago
Read 2 more answers
Which of these is a correct step I construing an angle bisector?
olasank [31]

Answer:

1) Place the compass point at the vertex of the angle and open it to any width. Draw an arc that intersects of the sides of the angle.

2) Place the compass point at the one of the intersection points. Place the pencil at the other intersection point. This sets the compass with.

3) Draw an arc inside the angle.

4) Move the compass point to the intersection point on the other side of the angle being sure to keep the compass width the same. Draw a second arc inside the angle.

5) Make a point where the 2 arcs intersect the angle. Use a straight edge to draw a ray from the vertex of the angle through the point.

8 0
4 years ago
Sales £18,500.00 staff £3367. what is this as a percentage
Oksi-84 [34.3K]
(3,367/18,500)=0.182 which is <em>18.2%</em>
7 0
4 years ago
The expression 10a+6c gives the cost (in dollars) for a adults and c children to eat at a buffet restaurant. A. The cost for 1 a
Liono4ka [1.6K]

Answer: The total cost is \$62 assuming the cost for 1 adult is \$5 and the cost for 1 child is \$2

Step-by-step explanation:

Assuming the cost for 1 adult is \$5 and the cost for 1 child is \$2:

a=\$5 and c=\$2

Then the expression that gives the total cost 10 a+6c is solved as:

10(\$5)+6(\$2)=\$62

4 0
4 years ago
Other questions:
  • Trying to help my sister with her homework can some help with #2. Please and thank you so much!
    7·1 answer
  • 162 is what percent of 200
    13·2 answers
  • Please help me how do i solve 0.75a = -9 using a two step equation
    12·2 answers
  • 3 sin^{2} x +cos 2x= (5/4)<br>answer in radians
    15·1 answer
  • Please help! thank you
    14·1 answer
  • Sorry i need help please quick
    5·1 answer
  • Please help meeeeeeeeeeeeeeee
    11·2 answers
  • Please help i’ll give you brainlest asap and please help me get this right!!
    11·2 answers
  • Find the Surface Area. I need the answer fast.
    10·2 answers
  • Solve for the product of three and four sevenths multiplied by two fifths.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!