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Ksju [112]
2 years ago
7

Clayton drove at a constant rate on the highway for a trip to the beach. He did not make any stops along the way. The distance C

layton had driven at any given time describes a linear function. At 3:00 p.m., he had driven 90 miles. At 4:30 p.m., he had driven 180 miles. Which statement about Clayton’s trip is true?
1.Clayton started driving at 1:30 p.m., and he drove 60 miles per hour.


2.Clayton started driving at 3:00 p.m., and he drove 60 miles per hour.



3.Clayton started driving at 1:30 p.m., and he drove 90 miles per hour.


4.Clayton started driving at 4:30 p.m., and he drove 90 miles per hour.
Mathematics
1 answer:
Nikolay [14]2 years ago
3 0

The answer is the first 1 !!

Here is how we see if it is true!

If Clayton drives 60 miles per hour, that means, <u>t</u>hat after one hour has passed, they should have traveled 60 miles!

If we look at the number of hours that have passed between 1:30 and 4:30, it is 3 hours.

If someone travels 60 miles every hour that has passed, and they traveled for 3 hours. To find how far they have traveled we just need to multiply 60 miles by 3 hours!

Let's solve that!

60 × 3 = 180 miles!

Clayton started driving at 1:30 pm and went 60 miles per hour.

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Answer: the length and width are

(x + 8) and (x + 8)

Step-by-step explanation:

The rug has an area represented by the expression

Area = 4x² + 64x + 256.

The factors in the factored expressions represent the length and width of the rug.

Dividing the the equation by 4, it becomes

x² + 16x + 64 = 0

We would find two numbers such that their sum or difference is 16x and their product is 64x^2.

The two numbers are 8x and 8x. Therefore,

x² + 8x + 8x + 64 = 0

x(x + 8) + 8(x + 8) = 0

The factors are

(x + 8)(x + 8)

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Step-by-step explanation:

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What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?​
Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

 Given the equation:

\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}

- Using the Difference of squares formula (a^2-b^2=(a+b)(a-b)) we can simplify the denominator of the right side of the equation:

\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}

- Multiply both sides of the equation by (m+3)(3-m) and simplify:

\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}

- Multiply both sides by m-3:

(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)

- Apply Distributive property and simplify:

(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0

- Divide both sides of the equation by -6:

\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0

- Factor the equation and solve for "m":

(m-3)^2=0\\\\m=3

In order to verify it, you must substitute m=3 into the equation and solve it:

\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}

<em>NO SOLUTION</em>

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