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3 years ago

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If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci

?(1 point)
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km

1 answer:

VladimirAG [237]3 years ago

6 0

Answer:

it’s the third option: 4,600,000 km

Explanation:

just took the test and that was correct

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A seesaw made of a plank of mass 10.0 kg and length 3.00 m is balanced on a fulcrum 1.00 m from one end of the plank. A 20.0-kg

lidiya [134]

Answer:

7.5 kg

Explanation:

We are given that

$m_1=10 kg$

Length of plank, l=3 m

Distance of fulcrum from one end of the plank=1 m

$m_2=20 kg$

We have to find the mass must be on the other end if the plank remains balanced.

Let m be the mass must be on the other end if the plank remains balanced.

In balance condition

$20\times 1=10\times (1.5-1)+m\times (1.5+0.5)$

$20=10(0.5)+2m$

$20=5+2m$

$2m=20-5=15$

$\implies m=\frac{15}{2}$

$m=7.5 kg$

Hence, mass 7.5 kg must be on the other end if the plank remains balanced.

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3 years ago

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A billiard ball moving at 6.00 m/s strikes a stationary ball of the same mass. after the collision, the first ball moves at 5.39

kodGreya [7K]

<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision.  </span>

<span>After collision... </span>

<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>

<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component)  </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>

<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion.  </span>

<span>Hope you understand!</span>

5 0

3 years ago

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We have compared the Terrestrial Planets and the Giant or Jovian Planets, but when we look at the 4 Giant Planets we can see tha

Ksivusya [100]

Answer:

i. Magnetic fields

ii. All 4 planets in appearance have deeper atmospheres and darker cloud.

iii. All the 4 Jovian planets rotates very quickly, with a range of 10 to 17 hours.

Explanation:

The Jovian planets is different from terrestrial planets in so many ways. The Jovian planets includes Jupiter , Saturn, Uranus and Neptune.

The major similarities shared by all of these 4 planets includes

i. Magnetic fields: Each of this Jovian planets have a strong magnetic field and are generated by electric currents in its rapidly sniping interior. The magnetosphere which is the region at which the planet magnetic field dominates is far more stronger in Jupiter than other Jovian planets . Although the magnetic field of Saturn , Neptune and Uranus works in similar way to Jupiter but are less stronger.

ii. All 4 planets in appearance have deeper atmospheres and darker cloud. The uppermost clouds of Jupiter and Saturn has more of ammonia crystals .The upper cloud of Neptune is composed of methane, The cloud of Uranus is deep.

iii. All the 4 Jovian planets rotates very quickly, with a range of 10 to 17 hours. The rotation period of Jupiter is the shortest among the Jovian planets which is around 9 hours 55 minutes. The rotation period of Neptune and Uranus take longer time than the other 2 Jovian planets( a little above 17 hours).

4 0

4 years ago

White light is an _____________ mixture of all the colors.<br> a) observable b) unequal c) equal

Musya8 [376]

Answer:

unequal

Explanation:

White light is a combination of all colors in the color spectrum.

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3 years ago

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A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long

KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

$h=Lsin30$

$h=10sin30$

$h=5m$

In the case of Inertia would be given by

$I = \frac{mR^2}{2}$

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

$I = mk^2$

$\frac{mR^2}{2}= mk^2$

$\frac{k^2}{R^2}=\frac{1}{2}$

Replacing in Energy conservation Equation we have that

Potential Energy = Kinetic Energy of Rolling Object

$mgh = \frac{1}{2}mv^2(1+\frac{k^2}{r^2})$

$9.8*5=\frac{1}{2}v^2(1+\frac{1}{2})$

$v^2 (1.5) = 98$

$v=8.0829m/s$

Therefore the correct answer is C.

3 0

3 years ago