Question

A) 9 b) 10 c) 12 d) 15 will give brainliest plz help

Answer 1

Answer:

b

Step-by-step explanation:

Given

2x + 2y = $\sqrt{180}$ = $\sqrt{36(5)}$ = 6$\sqrt{5}$

and y = $\frac{x}{2}$ , then

2x + (2 × $\frac{x}{2}$ ) = 6$\sqrt{5}$

2x + x = 6$\sqrt{5}$

3x = 6$\sqrt{5}$ ( divide both sides by 3 )

x = 2$\sqrt{5}$

and y = $\frac{2\sqrt{5} }{2}$ = $\sqrt{5}$

Then

xy = 2$\sqrt{5}$ × $\sqrt{5}$ = 2 × 5 = 10 → b

Answer 2

$y = \frac{x}{2}$

$2x + 2y = \sqrt{180} \\ = > 2x + 2( \frac{x}{2} ) = \sqrt{180} \\ = > 2x + x = \sqrt{2 \times 2 \times 3 \times 3 \times 5} \\ = > 3x = 2 \times 3\sqrt{5} \\ = > 3x = 6 \sqrt{5} \\ = > x = \frac{6 \sqrt{5} }{3} \\ = > x = 2 \sqrt{5}$

$x.y \\ = x \times \frac{x}{2} \\ = \frac{ {x}^{2} }{2} \\ = \frac{ {(2 \sqrt{5} )}^{2} }{2} \\ = \frac{4 \times 5}{2} \\ = \frac{20}{2} \\ = 10$

Answer:

10

Hope you could get an idea from here.

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