Question

30. If f(x)=1/2x-6 , what is the equation for f^-1(x)

Answer 1

Answer:

$f^{-1}$ (x) = 2x + 12

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = $\frac{1}{2}$ x - 6 ( multiply through by 2 to clear the fraction )

2y = x - 12 ( add 12 to both sides )

2y + 12 = x

change y back into terms of x with x = $f^{-1}$ (x) , then

$f^{-1}$ (x) = 2x + 12