9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
Answer:2405.0
Step-by-step explanation:
Answer:
x = 77 ft
Step-by-step explanation:
55 ÷ 45 = 1.222222222
1.222222222 x 63 = 77
<em><u>Question:</u></em>
Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?
<em><u>Answer:</u></em>
There will be $ 5920 in account after 15 years
<em><u>Solution:</u></em>
<em><u>The simple interest is given by formula:</u></em>

Where,
p is the principal
n is number of years
r is rate of interest
From given,
p = 3700
r = 4 %
t = 15 years
Therefore,

<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>
Total money = principal + simple interest
Total money = 3700 + 2220
Total money = 5920
Thus there will be $ 5920 in account after 15 years
(3x-5)+(x+1)=180
x=46
3(46)-5=133
m