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arsen [322]
2 years ago
8

There are 13,000 students attending a private college. There are 5,850evening students. What percent of all students are the eve

ning students?
Evening students are __% of all the college's students.
Mathematics
1 answer:
faust18 [17]2 years ago
4 0

Answer:

20%

Step-by-step explanation:

Because that is not all the school

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A consistent system of equations is a system with __________.
mr_godi [17]

D. Intersecting lines and lines that have the same equation.

Hope this helps :)

4 0
4 years ago
-8x^2+4x+5=0 using quadratic formula
daser333 [38]
So you want to solve for x?

It would be nice if this would easily factor:
(-4x + 5)(2x +1)  = 0    This will not work!

So you need to use the quadratic formula:
a = -8, b = 4, c = 5

x = \frac{-b+/-  \sqrt{b^{2}-4ac} }{2a}

x = (-4 +/- \sqrt{16-4(-8)(5)})/2(-8)
   = (-4 +/- \sqrt{16 + 160})/-16
   = (-4 +\sqrt{176})/-16
   = 1/4 - \sqrt{11}/4

6 0
3 years ago
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
6th grade math <br><br> 5x - 2
Naddik [55]

Answer:

-10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
At 8:00 am, a building casts a shadow 75 feet long. The angle where the ray from the sun met the ground is 50°. How tall is the
OlgaM077 [116]
The angle of elevation of shadow from building is 50 degrees
tan 50=height of building/length of shadow=h/75
h=75tan50=75(1.192)=89.38 feet
the height of the building is 89.38 feet
4 0
4 years ago
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