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Lelechka [254]
3 years ago
5

The Jackson family is putting down flooring in part of their basement. The floor in this part of the basement measures 10 feet w

ide by 20 feet long. The flooring that they want to use costs $2 per square foot. How much will the flooring cost in all? Explain
Mathematics
1 answer:
bixtya [17]3 years ago
7 0

10x20x2=$400

All you have to do is find the area of the floor(10x20=200),then you just multiple the area by the cost(200x$2=$400),and that is how you find the cost.

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At the end of a snow storm, Michael saw there was a lot of snow on his front lawn. The temperature increased and the snow began
QveST [7]

Answer:

x-intercept equals 10

interpretation is that, after 10 hours, all of the snow will be melted

Step-by-step explanation:

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3 years ago
I need this by tomorrow night 3/14/2017.
photoshop1234 [79]
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Step-by-step explanation:

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A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
(will mark as brainliest)
Helga [31]

Find the x and y-intercepts of the equation. Then calculate the points at constant intervals and plot and connect those points on a makeshift graph. A quadratic equation can have 2 solutions, 1 solution, or none. The corresponding graphs(if two solutions) would most probably cross over the x-axis twice.

Hope this helps.

4 0
3 years ago
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