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3 years ago

Which equation could represent the graph below?

Mathematics

1 answer:

coldgirl [10]3 years ago

8 0

Equation 2. If you look at the graph, you see that the slope is negative 3/4 because the rise over run is -3/4. The only equation with the slope -3/4 is 2, so the answer is 2.

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Which is a unit rate? A. 1/7 B. 48/4 C. 34/1 D. 40/5

BartSMP [9]

So,

Normally a unit rate will be x per 1y. Example: 60 miles/1hr.

Therefore, the option with the denominator as 1 would be the unit rate.

The correct option is C.

4 0

3 years ago

Read 2 more answers

Help me solve this please, im really bad at stuff like this

omeli [17]

Answer:

given

Step-by-step explanation:

5 0

3 years ago

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Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

$\int_{a}^{b}|f(x)-g(x)dx$

$\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx$

8 0

3 years ago

Anyone know what 422,391÷28=

saul85 [17]

15085.3929
Explanation
Use a calculator

5 0

3 years ago

Read 2 more answers

M=-4/3, point (0,-12)

postnew [5]

Y - y1 = m(x - x1)
slope(m) = -4/3
(0,-12)....x1 = 0 and y1 = -12
sub
y - (-12) = -4/3(x - 0) =
y + 12 = -4/3(x - 0) <=== point slope form

y + 12 = -4/3x
y = -4/3x - 12 <=== slope intercept form

y = -4/3x - 12
4/3x + y = -12
4x + 3y = -36 <=== standard form

3 0

3 years ago