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3 years ago

PLEASE HELP! (I’m in 8th grade so if you could try to make it soils like an 8th grader)

Physics

1 answer:

Nady [450]3 years ago

4 0

Answer:

Wave A and B have the same pitch, but Wave A is a quieter/softer sound. Wave A and B have the same pitch, but Wave B is a quieter/softer sound. Which sound wave shows the loudest sound?

Explanation:

i tried to help as quick as i could good luck

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Qwertyuiop hhffhhhhf fiuefhasuhs afbauyhsbvzskhbdv

mars1129 [50]

Answer:

gfhvgtrtjrgvfjrrgfrfftuyrisnhdvfcgfridkjhsybvvtfvjfcgvwjfccegvghcvgrcgvrekgvrkgvkvvrvkvfgkerruuyti

4 0

3 years ago

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What is an example of a invertebrate that doesn’t have an exoskeleton?

Tatiana [17]

Invertebrate means those organism which doesnot have backbone in their body .Some of the examples are:

1.Spider

2.earthworm

3.Starfish

4.Sea urchins.

hope this will help u a lot....

5 0

3 years ago

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Earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.

kobusy [5.1K]

The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x $10^{24}$ Kg

<h3>Relationship between Linear and angular speed</h3>

Linear speed is the product of angular speed and the maximum displacement of the particle. That is,

V = Wr

Where

V = Linear speed

W = Angular speed

r = Radius

Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.

a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed

W = 2 $\pi$ /T

W = (2 x 3.143) / (365.26 x 24)

W = 6.283 / 876624

W = 7.2 x $10^{-4}$ Rad/hr

The Earth’s average orbital speed V = Wr

V = 7.2 x $10^{-4}$ x 149.6 x $10^{6}$

V = 107225.5 kilometers per hours.

b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law

M = (4 $\pi ^{2}$ $r^{3}$ ) / G $T^{2}$

M = (4 x 9.8696 x 3.35 x $10^{24}$ ) / (6.67 x $10^{-11}$ x 7.68 x $10^{11}$ )

M = 1.32 x $10^{26}$ / 51.226

M = 2.58 x $10^{24}$ Kg

Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x $10^{24}$ Kg

Learn more about Orbital Speed here: brainly.com/question/22247460

#SPJ1

3 0

2 years ago

If a 340 g ball has 2.4 J of kinetic energy, what is it's velocity?

Leno4ka [110]

Answer:

Explanation:

i really dont know im a 4th grader

6 0

3 years ago

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A constant force is exerted on a cart that is initially at rest on a frictionless air track. The force acts for a short time int

Inessa05 [86]

Let F be the magnitude of the force applied to the cart, m the mass of the cart, and a the acceleration it undergoes. After time t, the cart accelerates from rest v₀ = 0 to a final velocity v. By Newton's second law, the first push applies an acceleration of

F = m a → a = F / m

so that the cart's final speed is

v = v₀ + a t

v = (F / m) t

If we force is halved, so is the accleration:

a = F / m → a/2 = F / (2m)

So, in order to get the cart up to the same speed v as before, you need to double the time interval t to 2t, since that would give

(F / (2m)) (2t) = (F / m) t = v

3 0

3 years ago