The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.
<h3>What is absolute pressure?</h3>
Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.
given,
diameter = 6 m
depth = h = 1.5 m
Atmospheric pressure = P₀ = 10⁵ Pa
a) absolute pressure
P = P₀ + ρ g h
P = 10⁵ + 1000 x 10 x 1.5
P = 1.15 x 10⁵ Pa
b) When two person enters into the pool,
mass of the two person = 150 Kg
weight of water level displaced exists equal to the weight of person.
Area of pool 
Height of the water rise
P = ρ g h
P = 1000 x 10 x 0.0106
P = 106.103 Pa
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Comets.
Small fragments of meteors, formed by ice and rock mixed consitute the comets.
Answer:
The correct answer is - option C. G.
Explanation:
In this reaction diagram, there is a representation of the reaction profile. The reaction profile shows the change that takes place during a reaction in the energy of reactants or substrate and products. In this profile, activation energy looks like a hump in the line, and the minimum energy required to initiate the reaction.
The overall energy of the reaction, including or excluding activation energy depends on the nature of the reaction if it is exothermic or endothermic. and products are represented by the G which shows the difference between the energy of the reactants and products.
It depends on the tempature of something or an object,
The Object has to go from hot to cold, that is a primary example of how heat transfer occurs
Answer:
Tension, T = 2038.09 N
Explanation:
Given that,
Frequency of the lowest note on a grand piano, f = 27.5 Hz
Length of the string, l = 2 m
Mass of the string, m = 440 g = 0.44 kg
Length of the vibrating section of the string is, L = 1.75 m
The frequency of the vibrating string in terms of tension is given by :
T = 2038.09 N
So, the tension in the string is 2038.09 N. Hence, this is the required solution.
