Explanation:
Let two charges are , such that, .............(1)
Distance between charges, r = 3 m
The force of repulsion between them is, F = 0.075 N
We can consider that both charges are positive, so that there exists the force of repulsion. The force of repulsion is given by :
.............(2)
On solving equation (1) and (2) we get :
(b) Now the force of attractive, F = -0.525 N
Let charges are such that, .............(3)
Force of attraction is given by :
.............(4)
Now on solving equation (3) and (4) we get :
and
Hence, this is the required solution.