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qaws [65]
2 years ago
8

A small car is pushing a large truck. They are speeding up.

Physics
1 answer:
Gnom [1K]2 years ago
3 0

The force of the truck on the car is equal to the force of the car on the truck.

<h3>What is Newton's third law of motion?</h3>
  • Newton's third law of motion states that action and reaction are equal and opposite.

Let the mass of the small car = m

Let the mass of the truck = M

The force exerted by the small car is calculated as;

F₁ = ma

The force exerted by the large truck is calculated as;

F₂ = Ma

According to Newton's third law, the magnitude of the two forces are equal but opposite in direction.

|F₁| = |F₂|

Thus, we can conclude that, the force of the truck on the car is equal to the force of the car on the truck.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

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You are standing next to your friend, ready to race across a 100 meter field. When the go signal is given, you take 5 seconds to
zhuklara [117]

1) 1.08 m/s^2

Explanation:

Acceleration is equal to the change in velocity divided by the time taken:

a=\frac{v-u}{\Delta t}

where

v is the final velocity

u is the initial velocity

\Delta t is the time taken

In this problem, we have:

- initial velocity: u = 0 (you start from rest)

- final velocity: v = 5.4 m/s

- time taken: \Delta t = 5 s

Therefore, the acceleration is

a=\frac{v-u}{\Delta t}=\frac{5.4 m/s-0}{5 s}=1.08 m/s^2


2) -0.54 m/s^2

We can calculate the acceleration to slow down using the same formula as before, but this time the data are as follows:

- initial velocity : u = 5.4 m/s

- final velocity : v = 0 (you come to a stop)

- time taken : \Delta t = 10 s

using the same formula, we find

a=\frac{v-u}{\Delta t}=\frac{0-5.4 m/s}{10 s}=-0.54 m/s^2

And the negative sign means it is a deceleration.

5 0
3 years ago
At what distance will a 45 W lightbulb have the same apparent brightness as a 130 W bulb viewed from a distance of 35 m ? (Assum
Sloan [31]

Answer:

20.6 m

Explanation:

P₁ = Power of first bulb = 45 W

P₂ = Power of second bulb = 130 W

r₁ = distance from the first bulb

r₂ = distance from the second bulb = 35 m

Using the equation

\frac{P_{1}}{r_{1}^{2}} = \frac{P_{2}}{r_{2}^{2}}

Inserting the values

\frac{45}{r_{1}^{2}} = \frac{130}{35^{2}}

r₁ = 20.6 m

5 0
4 years ago
Falling objects drop with an average acceleration of 9.8 m/sec/sec, or 9.8 m /s2. If an object falls from the top of a tall buil
Lena [83]

Use the velocity expression for uniform acceleration and solve for t: v = v0 + at. v0 is zero since the object is at rest. 49 m/s = a(t), and solve for t. t = 49 m/s / 9.8 = 5 seconds.

5 0
3 years ago
A person runs with a constant velocity of 1.2 m/s for 30 seconds. how far do they travel?
Nataliya [291]
They will travel 36 m
8 0
3 years ago
The force between two objects, each of charge +Q is measured as +F when the objects are separated a distance d apart. If the cha
dybincka [34]

Answer:

F'=4F

Explanation:

According to Coulomb's law, the magnitude of the force (F) between two  objects  with the same charge(+Q), separated a distance (d) apart, is defined as:

F=\frac{kQ^2}{d^2}

Here k is the Coulomb constant. The charge on each object is doubled, that is Q'=2Q:

F'=\frac{kQ'^2}{d^2}\\F'=\frac{k(2Q)^2}{d^2}\\F'=4\frac{kQ^2}{d^2}\\F'=4F

5 0
4 years ago
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