The force of attraction between things that have mass is called _______________

How long can a person dribble a ball when being closely guarded by a

Katena32 [7]

Answer:

four seconds

Explanation:

A player who catches the ball and is being closely guarded may hold the ball for four seconds, then dribble the ball for four seconds, then hold the ball for another four seconds, then pass, will not be in violation of this rule.

7 0

3 years ago

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. You may want to review ( pages 29

hjlf

The work that Sam should do in order to stop is the boat is the same as that of the kinetic energy of the object in order to counter its motion. Kinetic energy is calculated through the equation,
KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity.
Substituting,
KE = 0.5(1200kg)(1.2 m/s)²
<em>KE = 864 J</em>

5 0

3 years ago

Read 2 more answers

A piece of wire 25 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

Dmitry [639]

Answer:

10.87 m

Explanation:

Total length of the wire = 25 m

Let the length of one piece is y and other piece is 25 - y

Let the side of square is a.

So, 4 a = y

a = y / 4

And the side of triangle is b

3 b = (25 - y)

b = (25 - y) / 3

Area of square, A1 = side x side =

A1 = y² / 16

Area of equilateral triangle, A2 = $\frac{\sqrt{3}}{4}\times b^{2}$

$A_{2}=\frac{\sqrt{3}}{4}\frac{\left ( 25-y \right )^{2}}{9}$

Total area, A = A1 + A2

$A=\frac{y^{2}}{16}+\frac{\sqrt{3}}{4}\frac{\left ( 25-y \right )^{2}}{9}$

For maxima and minima, fins dA /dy

$\frac{dA}{dy}=\frac{y}{8}-\frac{1.732}{18} \times \frac{25-y}{1}$

It is equal to zero.

$\frac{y}{8}=\frac{1.732}{18} \times \frac{25-y}{1}$

9y = 173.2 -6.928 y

15.928 y = 173.2

y = 10.87 m

So, the length of wire to make square is 10.87 m.

3 0

3 years ago

The moon's mass is 7.35 × 1022 kg, and it moves around the earth approximately in a circle or radius 3.82 × 105 km. The time req

Stolb23 [73]

Explanation:

It is given that,

Mass of moon, $m=7.35\times 10^{22}\ kg$

Radius of circle, $r=3.82\times 10^{5}\ km=3.82\times 10^{8}\ m$

The time required for one revolution is 27.3 days, t = 27.3 days

1 day = 86400 seconds

27.3 days = 2358720 seconds

Let v is the speed of moon around the circular path. It is given by :

$v=\dfrac{2\pi r}{T}$

$v=\dfrac{2\pi \times 3.82\times 10^{8}\ m}{2358720\ s}$

v = 1017.57 m/s

Let F is the centripetal force acting on the moon. It is given by :

$F=\dfrac{mv^2}{r}$

$F=\dfrac{7.35\times 10^{22}\ kg\times (1017.57\ m)^2}{3.82\times 10^{8}\ m}$

$F=1.99\times 10^{20}\ m/s^2$

So, the centripetal force that must act on the moon is $1.99\times 10^{20}\ m/s^2$ . The gravitational force that the earth exerts on the moon at that same distance is also equal to $1.99\times 10^{20}\ m/s^2$ . Hence, this is the required solution.

6 0

3 years ago

You're outside on a cold day (Tout = 0 °C)listening to your iPod with an external circular speaker having a diameter 0.0550 m. B

JulijaS [17]

1). The change would be due to the expansion of the speaker, so we need to know what substances comprise the speaker. #2). A speaker with a diameter of 0.055m is not too good at reproducing 8.54 KHz. (3). I believe this is a bogus question.

8 0

2 years ago

The force of attraction between things that have mass is called ________________.