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Tju [1.3M]
2 years ago
5

Does anyone have the genetics unit test? i need answers now or ill have to go to boot camp please helpppp

Physics
2 answers:
xxTIMURxx [149]2 years ago
4 0

Answer:

we don't know what school or class you go to so there's no way of knowing if we have the same one, your best bet is to ask question by question until you have all the answers

Marina CMI [18]2 years ago
3 0

Answer:

I do not know, but if you post some of the questions that are on the test we might be able to help.

Explanation:

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The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about 4.1 x 103 Calories. If a
Luba_88 [7]

Answer:

t = 70.13 hours

Explanation:

As we know that 1 lb fat can be used to expend 4.1 k Calorie of energy

so here we know that we have to use 7.56 lb of body fat

so here the total energy that is to be utilized is given as

Q = (4.1 \times 10^3)(7.56)

so we will have

Q = 30996 Calorie

now we know that runner expends the energy at rate of 1850 kJ/h

so we have

E = 1850 \times 10^3 kJ/h

so it is

E = 0.44 \times 10^3 calorie/h

now we know that time to burn this energy is given as

t = \frac{Q}{E}

t = \frac{30996}{0.44 \times 10^3}

t = 70.13 hours

5 0
4 years ago
I need to know what a-e is. Please and thank you!
beks73 [17]
The different types of energy transfers are convection, conduction, and radiation. 
I'm not too sure on the second one but thermodynamics relates thermal energy, kinetic energy, and potential energy. I'm basing this on the formulas of the laws of thermodynamics, but it could also be temperature, heat, or work.
6 0
3 years ago
Block 1, of mass m₁ = 1.30 kg , moves along a frictionless air track with speed v₁ = 29.0 m/s. It collides with block 2, of mass
Alecsey [184]

Answer:

a. 37.7 kgm/s b. 0.94 m/s c. -528.85 J

Explanation:

a. The initial momentum of block 1 of m₁ = 1.30 kg with speed v₁ = 29.0 m/s is p₁ = m₁v₁ = 1.30 kg × 29.0 m/s = 37.7 kgm/s

The initial momentum of block 2 of m₁ = 39.0 kg with speed v₂ = 0 m/s since it is initially at rest is p₁ = m₁v₁ = 39.0 kg × 0 m/s = 0 kgm/s

So, the magnitude of the total initial momentum of the two-block system = (37.7 + 0) kgm/s = 37.7 kgm/s

b. Since the blocks stick together after the collision, their final momentum is p₂ = (m₁ + m₂)v where v is the final speed of the two-block system.

p₂ = (1.3 + 39.0)v = 40.3v

From the principle of conservation of momentum,

p₁ = p₂

37.7 kgm/s = 40.3v

v = 37.7/40.3 = 0.94 m/s

So the final velocity of the two-block system is 0.94 m/s

c. The change in kinetic energy of the two-block system is ΔK = K₂ - K₁ where K₂ = final kinetic energy of the two-block system = 1/2(m₁ + m₂)v² and K₁ = final kinetic energy of the two-block system = 1/2m₁v₁²

So, ΔK = K₂ - K₁ = 1/2(m₁ + m₂)v² - 1/2m₁v₁² = 1/2(1.3 + 39.0) × 0.94² - 1/2 × 1.3 × 29.0² = 17.805 J - 546.65 J = -528.845 J ≅ -528.85 J

7 0
3 years ago
How can you show positive body languages with your mouth
sergey [27]
By just smiling. It normally makes you look more happy.And if your happy that's positive body languge
7 0
4 years ago
Consider two spaceships, each traveling at 0.50c in a straight line. Ship A is moving directly away from the Sun and ship B is a
attashe74 [19]

Answer:

The velocity of the light will be 1.0c only

Explanation:

The velocity of the light measured in the case given in question will be 1.0c only.

This is due to the fact that the velocity of light is never relative. The velocity of the light is maximum

The velocity of the light cannot be scaled down in no case

Thus, the velocity of the light remains as constant.

Hence, the velocity of the light measured will be 1.0c although the ships have relative velocity.

3 0
3 years ago
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