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3 years ago

What is the formula to calculate acceleration

Physics

2 answers:

ladessa [460]3 years ago

7 0

Answer:

Im going to link a picture should help you better then me explaining

Explanation:

yan [13]3 years ago

6 0

Explanation:

<em> </em><em>your</em><em> </em><em>formu</em><em>la</em><em> </em><em>is</em><em> </em><em>here</em><em> </em>

<em>hope </em><em>it's </em><em>helps</em><em> </em><em>u</em>

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A 5 kg pineapple is hanging completely still in mid air on a string and suddenly explodes

11111nata11111 [884]

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

3(15) + 2(v) = 0

v = - 22.5 m/s

v = 22.5 m/s downward

3 0

3 years ago

A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the

Vesna [10]

So, based on the angle values that have been found, the angle of elevation of the nozzle can be <u>16° or 74°</u>.

<h3>Introduction</h3>

Hi ! This question can be solved using the principle of parabolic motion. Remember ! When the object is moving parabolic, the object has two points, namely the highest point (where the resultant velocity is 0 m/s in a very short time) and the farthest point (has the resultant velocity equal to the initial velocity). At the farthest distance, the object will move with the following equation :

$\boxed{\sf{\bold{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}}}$

With the following condition :

$\sf{x_{max}}$ = the farthest distance of the parabolic movement (m)
$\sf{v_0}$ = initial speed (m/s)
$\sf{\theta}$ = elevation angle (°)
g = acceleration due to gravity (m/s²)

<h3>Problem Solving :</h3>

We know that :

$\sf{x_{max}}$ = the farthest distance of the parabolic movement = 2.5 m
$\sf{v_0}$ = initial speed = 6.8 m/s
g = acceleration due to gravity = 9.8 m/s²

<h3>What was asked :</h3>

$\sf{\theta}$ = elevation angle = ... °

Step by Step :

Find the equation value $\sf{\bold{theta}}$ (elevation angle)

$\sf{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}$

$\sf{x_{max} \cdot g = (v_0)^2 \cdot \sin(2 \theta)}$

$\sf{\frac{x_{max} \cdot g}{(v_0)^2} = \sin(2 \theta)}$

$\sf{\frac{2.5 \cdot 9.8}{(6.8)^2} = \sin(2 \theta)}$

$\sf{\frac{24.5}{46.24} = \sin(2 \theta)}$

$\sf{\sin(2 \theta) \approx 0.53}$

$\sf{\cancel{\sin}(2 \theta) \approx \cancel{\sin}(32^o)}$

Find the angle value of the equation by using trigonometric equations. Provided that the parabolic motion has an angle of elevation 0° ≤ x ≤ 90°.

First Probability

$\sf{2 \theta = 32^o + k \cdot 360^o}$

$\sf{\theta = 16^o + k \cdot 180^o}$

→ $\sf{k = 0 \rightarrow 16^o + 0 = 16^o}$ (T)

→ $\sf{k = 1 \rightarrow 16^o + 180^o = 196^o}$ (F)

Second Probability

$\sf{2 \theta = (180^o - 32^o) + k \cdot 360^o}$

$\sf{2 \theta = 148^o + k \cdot 360^o}$

$\sf{\theta = 74^o + k \cdot 180^o}$

→ $\sf{k = 0 \rightarrow 74^o + 0 = 74^o}$ (T)

→ $\sf{k = 1 \rightarrow 74^o + 180^o = 254^o}$ (F)

$\boxed{\sf{\therefore \theta \{16^o , 74^o\} }}$

<h3>Conclusion</h3>

So, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.

8 0

3 years ago

Connective Tissue in a tendon is

mariarad [96]

Overview. A tendon is a fibrous connective tissue which attaches muscle to bone. Tendons may also attach muscles to structures such as the eyeball. A tendon serves to move the bone or structure.

4 0

3 years ago

Which is the best example of a scientific discovery resulting from new technology?

Anna11 [10]

third

Explanation:

i think so because finding structure of dna can help a lot for well being of human being

8 0

3 years ago

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon-population sy

Genrish500 [490]

The question is incomplete. The complete question is :

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon population system move? Assume the population is 7 billion, the average human has a mass of 65 kg, and that the population is evenly distributed over both the Earth and the Moon. The mass of the Earth is 5.97×1024 kg and that of the Moon is 7.34×1022 kg. The radius of the Moon’s orbit is about 3.84×105 m.

Solution :

Given :

Mass of earth, $M_e = 5.97 \times 10^{24} \ kg$

Mass of moon, $M_m = 7.34 \times 10^{22} \ kg$

Mass of each human, $m_p =65 \ kg$

Therefore mass of total population, $M_p = 65 \times 7 \times 10^{9} \ kg$

$M_p = 4.55 \times 10^{11} \ kg$

Let the earth is at the origin of the coordinate system. Then,

Since $M_e>> M_p$

$M_m>> M_p$

Hence if we shift all the population on the moon there will be negligible change in the mass of the moon and earth. Hence there will not be any significant shift on the centre of mass. i.e.

$X_{cm} = \frac{5.97 \times 10^{24}+ 7.34 \times 10^{22} \times 3.84 \times 10^5}{5.97 \times 10^{24}+ 7.34 \times 10^{22}}$

$= 4.68 \times 10^6 \ m$

$4.68 \times 10^3 \ km$ from the earth.

3 0

3 years ago

What is the formula to calculate acceleration​

What is the formula to calculate acceleration