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san4es73 [151]
2 years ago
13

How much heat is released when 12. 0 grams of helium gas condense at 2. 17 K? The latent heat of vaporization of helium is 21 J/

g. â€""250 J â€""26 J 26 J 250 J.
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
7 0

The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J

The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.

However, since we are required to determine heat released when the helium gas condenses.

The heat of condensation per gram is; -21 J/g.

Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.

Approximately, -250J.

Read more on latent heat:

brainly.com/question/19863536

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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn
Gekata [30.6K]

Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i) for all i,i',j and for X_n in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that j=2, i=1, i'=0 then we have this:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}

Because we can only have j=2, i=1, i'=0 if we have this:

Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0, from definition given X_n = Y_n + Y_{n-1}

With i=1, i'=0 we have that Y_n =1 , Y_{n-1}=0, Y_{n-2}=0

So based on these conditions Y_{n+1} would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that j=2, i=1, i'=2 for this case in order to satisfy the definition then Y_n =0, Y_{n-1}=1, Y_{n-2}=1

But on this case that means X_{n+1}\neq 2 and on this case the probability P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0, so we have a counter example and we have that:

P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i) for all i,i', j so then we can conclude that we don't have a Markov chain for this case.

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3 years ago
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Step-by-step explanation:

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2 years ago
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Nonamiya [84]

Answer:

The third option. (the one where it intersects on the y line)

Step-by-step explanation:

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3 years ago
of the 75 boys in the 7th grade class, 25 participate in at least one sport . of the 120 girls in 7th grade class 30
hoa [83]

Answer:

"No, the relationship is NOT proportional"

Step-by-step explanation:

<u>Complete Question:</u>

Of the 75 boys in the 7th grade class, 25 participate in at least one sport. Of the 120 girls in 7th grade class 30 participate in at least one sport. Is this relationship proportional?

We have to see the ratio of each and if they are equal (after reducing), we can say they are proportional.

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25 participate in atleast 1 sport and there are total of 75. Hence, ratio is

25 : 75 = 1 : 3

Girls:

30 particiapte in atleast 1 sport and there are toal of 120. hence ratio is:

30 : 120 = 1 : 4

So, the relationship is NOT proportional

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