with a mean of 32 minutes and a standard deviation of 5 minutes. What is the probability that a randomly selected customer will
have to wait less than 21 minutes, to the nearest thousandth?
1 answer:
Answer:
1.39%
Step-by-step explanation:
(21 - 32) / 5 = -2.2 z score
= 0.0139 so there is a 1.39% probability
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