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2 years ago

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Graph all solutions on a number line and provide the corresponding interval notation. 1. 3x + 5>-4 2. 2x+1> -1 3.5-6y <

-1 4.7-9y> 43 5.6-a≤6

1 answer:

kykrilka [37]2 years ago

4 0

Graphs attached

Done!

Hopw it helps

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Monica drinks 0.125 liters of milk during breakfast and 0.20 liters of milk after dinner everyday. Find the total amount of milk

pogonyaev

Answer:

A. .325L

Step-by-step explanation:

All you have to do is had .125 with .20 to get your answer

4 0

3 years ago

Read 2 more answers

Find the value ofx. O is the center of the circle. Round your answer to the nearest hundredth.

lyudmila [28]

Answer:

A. In a binomial distribution, the value ofx represents the number of successes in n trials, while in a geometric distribution, the value ofx represents the first trial that results in a success.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

The most important difference is that in the binomial distribution, the value of x represents the successes in n trials.

And by the other hand in the geometric distribution, x represents the number of failures before you get a success in a series of Bernoulli trials.

So then the best answer for this case is:

A. In a binomial distribution, the value of x represents the number of successes in n trials, while in a geometric distribution, the value ofx represents the first trial that results in a success.

Step-by-step explanation:

8 0

3 years ago

A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe

Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

$\omega=\frac{v}{r}$ ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

$47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}$

next, you replace the values of v and r in the equation (1):

$\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}$

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0

3 years ago

The prism shown has a volume of 35cm³. Work out the height of the triangular cross section. The length going back is 7cm and the

Gre4nikov [31]

Answer:

2.5 cm

Step-by-step explanation:

The volume of a triangular prism is cross section × length.

The cross section area is the triangle area. The triangle length is 4 cm, the height is not given. The length of the triangular prism is 7cm.

4 × h × 1/2 × 7 = 35

14h = 35

h = 35/14

h = 5/2

The height of the triangular cross section is 2.5 cm.

3 0

3 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

3 years ago