Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
Answer: 5/4 = 1 2/8
Step-by-step explanation: That's the answer
What do you need to find I need to know that so I can solve it
Answer:
1.01 m8
Step-by-step explanation:
Answer:
a) 0.018
b) 0
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 14.4 in
Standard Deviation, σ = 1 in
We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.
Formula:
a) P(breadth will be greater than 16.5 in)
P(x > 16.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.
b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)
Formula:
P(x > 16.5)
Calculation the value from standard normal z table, we have,
There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in
