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nekit [7.7K]
3 years ago
7

Rewrite

7D" id="TexFormula1" title="\frac{2}{x^{2}-x-12 } and \frac{1}{x^{2}-16 }" alt="\frac{2}{x^{2}-x-12 } and \frac{1}{x^{2}-16 }" align="absmiddle" class="latex-formula"> as equivalent rational expressions with the lowest common denominator.
Provide your answer below:
___ , ___
Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0
Dhduudifufjfhxh h h hutch u u u ucuchch hcuuchchccuucucucucucucucucucucucuc
gogolik [260]3 years ago
4 0

Answer:

2(x+4)/(x+3)(x-4)(x+4) and 1(x+3)/(x+3)(x-4)(x+4)

Step-by-step explanation:

Factor x^2-x-12: (x+3)(x-4)

Factor x^2-16: (x+4)(x-4)

So, LCD would be (x+3)(x-4)(x+4)

Rewritten: 2(x+4)/(x+3)(x-4)(x+4) and 1(x+3)/(x+3)(x-4)(x+4)

I hope this helped and have a good rest of your day!

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Step-by-step explanation:

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zhannawk [14.2K]

Step-by-step explanation:

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\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

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