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3 years ago

5

The density of aluminum is 2.7 g/mL if I add a piece of aluminum to a graduated cylinder of water in the water level increases b

y 8.2 ML what is the mass of the piece of aluminum
3.0 g
22 g
5.5 g
0.33 g

1 answer:

viva [34]3 years ago

8 0

The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.

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2 years ago

How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?

Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

$C_{6}H_{8}O_{6}$

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We have that:

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$C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)$

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

$C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}$

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

$C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol$

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

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3 years ago

What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]

valentinak56 [21]

Answer: The percentage by mass of sulphur in $Al_2(SO_4)_3$ is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

${\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%$

Given: mass of sulphur = 32 g/mol

mass of $Al_2(SO_4)_3$ = 342 g/mol

Putting in the values we get:

${\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%$

The percentage by mass of sulphur in $Al_2(SO_4)_3$ is 9.36%

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3 years ago