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Sophie [7]
3 years ago
5

The density of aluminum is 2.7 g/mL if I add a piece of aluminum to a graduated cylinder of water in the water level increases b

y 8.2 ML what is the mass of the piece of aluminum
3.0 g
22 g
5.5 g
0.33 g
Chemistry
1 answer:
viva [34]3 years ago
8 0
The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.
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How many of each subatomic particle type does each of the following atoms contain: a. 90_Ag b. barium-132
Kryger [21]

<u>Answer:</u> Silver has 47 electrons, 47 protons and 43 neutrons. Barium has 56 electrons, 56 protons and 76 neutrons.

<u>Explanation:</u>

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

  • <u>For Silver:</u>

Atomic number = 47

Mass number = 90

Atomic number = Number of protons = Number of electrons = 47

Number of neutrons = Mass number - Atomic number = 90 - 47 = 43

Hence, silver has 47 electrons, 47 protons and 43 neutrons.

  • <u>For Barium:</u>

Atomic number = 56

Mass number = 132

Atomic number = Number of protons = Number of electrons = 56

Number of neutrons = Mass number - Atomic number = 132 - 56 = 76

Hence, barium has 56 electrons, 56 protons and 76 neutrons.

7 0
3 years ago
What is the first step in the scientific method? A. form a hypothesis B. illustrate the process C. observe and ask questions D.
Tom [10]
The answer would be C) Observe and ask questions because if we do process of elimination we see that drawing conclusions is NOT the first step, forming a hypothesis and illustrating the process is part of the method, but NOT the first step.
3 0
3 years ago
Read 2 more answers
The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be
Stels [109]

Explanation:

1) Initial mass of the Cesium-137=N_o= 180 mg

Mass of Cesium after time t = N

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

Half life of the cesium-137 = t_{1/2}=30 years[p/tex]where,&#10;[tex]N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope

\lambda = rate constant

N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

N=180mg\times e^{-\frac{0.693}{30 years}\times t}

Mass that remains after t years.

N=180 mg\times e^{0.0231 year^{-1}\times t}

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

N_o=180 mg

t_{1/2}= 30 yeras

N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

N_o=180 mg

t_{1/2}= 30 yeras

N = 1 mg

t = ?

1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}

\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0
3 years ago
The presence of hydrogen bond in most molecules is responsible for the following except
-Dominant- [34]
That answer is either 3 or 4, but I truly forgot which of the two.
5 0
3 years ago
Read 2 more answers
Write the number 345 in scientific notation, with the same number of significant figures:
uranmaximum [27]

Answer:

3.45 x 10^2

Explanation:

345= 3 SF

3.45 x 10^2= 3 SF

8 0
3 years ago
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