<h2>
Answer: O: 1s22s22p4</h2>
Explanation: In writing the electron configuration for oxygen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for O go in the 2s orbital. The remaining four electrons will go in the 2p orbital. Therefore the O electron configuration will be 1s22s22p4.
The first thing to do is to convert the mass of sodium
sulfate to moles. Since the given is in milligrams convert it to grams which
would be 0.02824 grams. The number of moles can be calculated by dividing the
converted weight with the given molar mass which is 139.04 g/mol. The number of
mols in the solution is 2.03x10^-4 mols. Then divide the number of moles with
0.02355 L. The molarity of the solution is 0.00862 M.
Answer:
we need to look at what actually happens to reactant molecules during a chemical. in order for the reaction to take place , some or all of the chemical bonds in the reactants must be broken so that the new bonds, those of the products , can form.
Answer:
183N
Explanation:
183N we have to add both mass
Reactivity of metals depends on the tendency to lose electrons. ... As we move down the group, the tendency to gain electrons decreases because as the atomic size increases, the effective nuclear charge decreases.
