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Sveta_85 [38]
2 years ago
11

3. Which statement would be true of a membrane-bound protein that works in conjunction with a sodium–potassium pump during secon

dary active transport?
It will block a small molecule from moving across the cell membrane in response to an increase in concentration of an ion in the external environment.
It will be able to transport an ion in both directions across the cell membrane and a small molecule in one direction.
Its conformation will change when both an ion and a small molecule bind to it.
It will move a small molecule across the cell membrane in response to a build-up in concentration of the molecule in the external environment.
Biology
1 answer:
kow [346]2 years ago
4 0

Answer:

i

Explanation:

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DNA contains the instructions to help the cell survive. They help the cell produce protein in the stages of protein synthesis.

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How does science impact your life everyday? Would you choose a career in science and why?
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List the five classes of antibody heavy chains and provide one function for each.
Lesechka [4]

Answer:

IgM, IgA, IgE, IgD and IgG

Explanation:

IgM functions in the initial response to offence.

IgA is important for protection of mucus membranes such as in saliva, sweat, tears and gastric fluid.

IgE is active during allergic reactions and defense against infections.

IgD is found on the surface of lymphocytes and is activated upon contact with antigens.

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8 0
2 years ago
In Drosophila, the genes for body coloration and eye size are on different chromosomes. Normal-colored bodies are dominant to eb
Yuri [45]

Answer:

225 flies

Explanation:

Let gene for body colour : A

Let gene for eye type : B

Parent 1 : normal body and normal eyes = AABB

Parent 2: ebony body and eyeless = aabb

F1 : AABB X aabb = AaBb ( all have normal body and normal eye )

F1 progeny is self crossed given that the two genes are on different chromosomes which means they show independent assortment:

AaBb X AaBb =

A_B_ = normal body, normal eyes = 9

aaB_ = ebony body, normal eyes = 3

A_bb = normal body, eyeless  = 3    

aabb = ebony body, eyeless  =   1

Hence the ratio is 9 : 3 : 3 : 1

Out of the 400 flies:

(9/16) * 400 = 225 flies have normal body colour and normal eyes

7 0
2 years ago
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