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dybincka [34]
2 years ago
6

Find the perpendicular distance from the point(5,6) to the line -2x+3y+4=0​

Mathematics
1 answer:
ra1l [238]2 years ago
5 0

Step-by-step explanation:

clicking a link in the current visible page

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How can I solve for t?
Alexxandr [17]

Answer:

This is not possible with 2 equal symbols

8 0
3 years ago
Am I finding the area of this wierd shape correctly if not what am I doing wrong?
saw5 [17]

Answer:

8 ft^2

Step-by-step explanation:

Sadly, you are doing this incorrectly.

The easiest way to find the area of this shape is to separate it into a square and a triangle.

This will leave you with a square with the dimentions 2x2 a triangle with a base of 4 and a height of 2.

The area of the square is 4 ft^2

Using the equation for the area of a triangle

A=\frac{1}{2} bh

We can plug in our 2 know values to get

A=\frac{1}{2} (4)(2)\\A=4

Now we can take the sum of the areas of these two shapes to get a total area of 8 ft^2

3 0
3 years ago
Find (a) the amplitude, (b) the wavelength, (c) the period, and (d) the speed of a wave whose displacement is given by y= 1.5 co
leonid [27]

Answer with Step-by-step explanation:

We are given that displacement of wave

y=1.5cos(0.68x+37t)

Where y in cm  and t in sec.

a.Compare it with

y=Acos(kx+\omega t)

Amplitude of wave=A

We get A=1.5

Amplitude=A=1.5  cm

b.k=0.68

\frac{2\pi}{\lambda}=0.68

\lambda=\frac{2\times 3.14}{0.68}=9.2 cm

Using \pi=3.14

Wavelength of the wave=9.2 cm

c.Period=\frac{2\pi}{T}=\omega

\frac{2\pi}{T}=37

T=\frac{2\times 3.14}{37}=0.17 s

The period of the wave=0.17 s

Speed of the wave=\nu \lambda=\frac{\lambda}{T}=\frac{9.2}{0.17}

Speed of the wave=54.1 cm/s

8 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
2. The Lamberti family is building a rectangular deck that measures 30 feet by 22 feet. They need to run an electric line across
schepotkina [342]

Answer:

37 ft

Step-by-step explanation:

The Pythagorean theorem tells you the length of the diagonal is the square root of the sum of the squares of the side lengths:

diagonal = √(30^2 +22^2) = √1384 ≈ 37 . . . . feet

6 0
3 years ago
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