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3 years ago

The moving charge in the wire causes the compass to deflect; this is because

Physics

1 answer:

Marizza181 [45]3 years ago

6 0

A. the moving charge induces a magnet field

B. the energy of the charge pushes on the compass

C. the electrons heat up the wire, causing the compass to deflect

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A venturi meter is a device for measuring the speed of a fluid within a pipe. The drawing shows a gas flowing at a speed v2 thro

yarga [219]

Answer:

$V_2=6.17\ m/s$

$Q=0.49\ m^3/s$

Explanation:

Given that

$A_1=0.03m^2$

$A_2=0.08m^2$

We know that from continuity equation

$Q=A_1V_1=A_2V_2$

$A_1V_1=A_2V_2$

$0.3V_1=0.08V_2$

$V_1=2.66V_2$

Now from energy equation

$P_1+\dfrac{1}{2}\rho V_1^2=P_2+\dfrac{1}{2}\rho V_2^2$

$P_2-P_1=\dfrac{1}{2}\rho V_1^2-\dfrac{1}{2}\rho V_2^2$

$140=\dfrac{1}{2}\times 1.2\times 7.11\times V_2^2-\dfrac{1}{2}\times 1.2\times V_2^2$

$V_2=6.17\ m/s$

$Q=A_2V_2$

Q=6.17 x 0.08

$Q=0.49\ m^3/s$

7 0

3 years ago

A 8.0-g bullet with an initial velocity of 115.0 m/s lodges in a block of wood and comes to rest at a

Gnesinka [82]

A. When your fire a bullet into the air, it typically takes between 20 and 90 second for it to come down,depending on the angle it was fired at,its muzzle velocity and caliber.

3 0

3 years ago

a 4lb ball is travelling in a circle radius 3ft speed 6ft/s. the attached cord pulled through the center has constant speed 2ft/

lora16 [44]

Answer:

Explanation:

Circle motion

Weight=4lb

Radius=3ft

Velocity Vb= 6ft/s

Velocity Vr=2ft/s

Velocity Vo=12

V2=√Vo²+Vr²

12=√Vo²+2²

Square both side

144=Vo²+4

Vo²=140

Vo=11.83ft/s

Applying conservation of angular momentum

Ha1=Hb2

MbVbr1=MbVor2

r2=Vbr1/Vo

r2=6×3/11.83

r2=1.52ft

The require time is written as.

∆r=Vrt

t=∆r/Vr

t=r1-r2/Vr

t=3-1.52/2

t=0.74sec

4 0

4 years ago

1. When asteroids collided some of the broken materials fall into Earth's orbit. What do

Kazeer [188]

I believe it is meteoroids

6 0

3 years ago

Read 2 more answers

We investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on solid ground with a

AlexFokin [52]

Answer:

Time is 14.8 s and cannot landing

Explanation:

This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same

Calculate the time to stop, where it has zero speed

Vf² = Vo² + a t

t = - Vo² / a

t = - 110²/(-7.42)

t = 14.8 s

This is the time it takes to stop the jet

Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero

Vf² = Vo² + 2 to X

X = -Vo² / 2 a

X = -110² / 2 (-7.42)

X = 815.4 m

Since this distance is greater than the length of the runway, the jet cannot stop

Let's calculate the speed you should have to stop on a track of this size

Vo² = 2 a X

Vo = √ (2 7.42 800)

Vo = 109 m / s

It is conclusion the jet must lose some speed to land on this track

4 0

3 years ago