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Klio2033 [76]
4 years ago
7

a 4lb ball is travelling in a circle radius 3ft speed 6ft/s. the attached cord pulled through the center has constant speed 2ft/

s. how much time for the ball to reach 12 ft/s
Physics
1 answer:
lora16 [44]4 years ago
4 0

Answer:

Explanation:

Circle motion

Weight=4lb

Radius=3ft

Velocity Vb= 6ft/s

Velocity Vr=2ft/s

Velocity Vo=12

V2=√Vo²+Vr²

12=√Vo²+2²

Square both side

144=Vo²+4

Vo²=140

Vo=11.83ft/s

Applying conservation of angular momentum

Ha1=Hb2

MbVbr1=MbVor2

r2=Vbr1/Vo

r2=6×3/11.83

r2=1.52ft

The require time is written as.

∆r=Vrt

t=∆r/Vr

t=r1-r2/Vr

t=3-1.52/2

t=0.74sec

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our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three
Licemer1 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The torque produced by the pile of rocks is \tau = 35.63\ N \cdot m  

b

The distance of the single for equilibrium to occur is r_s =1.62 \ m

Explanation:

From the question we are told that

     The mass of the left rock is  m_s = 2.25 \ kg

     The mass of the rock on the right m_p = 10.1 kg

    The distance from  fulcrum to the center of the pile of rocks is  r_p = 0.360 \ m

   

Generally the torque produced by the pile of rock is mathematically represented as

           \tau = m_p * g * r_p

Substituting values

         \tau = 10.1 * 9.8  * 0.360                  

          \tau = 35.63\ N \cdot m      

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

   The torque due to the single rock is

           \tau = m_s  * g * r_s

At equilibrium the both torque are equal

            35.63 = m_s * r_s * g

Making r_s the subject of the formula

             r_s = \frac{35.63 }{m_s * g}

Substituting values

            r_s = \frac{35.63 }{2.25 * 9.8}

            r_s =1.62 \ m

6 0
3 years ago
Whoever answers correctly gets brainlist!
UNO [17]

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5 0
3 years ago
Read 2 more answers
a sample contains 100 g of radioactive isotope. How much radioactive isotope will remain in the sample after 1 half-life?
kap26 [50]

Answer:

\huge\boxed{50g}

Definition:

Half-life- The time taken for half of the radioactive isotopes to decay.

Explanation:

How does radioactive decay work? Radioactive decay is a process by which unstable nuclei become more stable through the emission of alpha or beta particles or gamma rays.

Since a half-life is the time taken for half of the isotopes to decay, we can simply divide the initial mass of 100 grams by 2; this gives us 50 grams.

1) Divide 100g by 2.

\frac{100g}{2}=50g

8 0
2 years ago
During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca
Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

the centripetal acceleration is given as,

a=\frac{v^2}{r}

r is the radius of the loop

on substituting the respective values, we get

8\times9.81=\frac{340^2}{r}

or

r = 1472.98 m

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Answer:

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