Answer:
speed of golf ball is 1.15 × m/s
and % of uncertainty in speed = 2.07 × %
Explanation:
given data
mass = 45.9 gram = 0.0459 kg
speed = 200 km/hr = 55.5 m/s
uncertainty position Δx = 1 mm = m
to find out
speed of the golf ball and % of speed of the golf ball
solution
we will apply here heisenberg uncertainty principle that is
uncertainty position ×uncertainty momentum ≥ ......1
Δx × ΔPx ≥
here uncertainty momentum ΔPx = mΔVx
and uncertainty velocity = ΔVx
and h = 6.626 × Js
so put here all these value in equation 1
× 0.0459 × ΔVx =
ΔVx = 1.15 × m/s
and
so % of uncertainty in speed = ΔV / m
% of uncertainty in speed = 1.15 × / 55.5
% of uncertainty in speed = 2.07 × %
Answer:
v = 87.5 km/h
Explanation:
To find the speed of the car you use the following formula:
(1)
x: distance traveled by the car = 350km
t: time = 4h
you replace the values of x and t in the equation (1):
hence, the speed of the car is 87.5km/h
Answer:
The vector equation of the line is
Parametric equations for given line are
Explanation:
The vector equation of the line is given by
r₀ = (7, -8, 3)
v = (1, 6, -13)
At these points the vector equation for this line is:
Parametric equations for given line are
The net force on the student is A) -294 N
Explanation:
Neglecting air resistance, there is only one force acting on the student: the force of gravity, which is given by
where
m is the mass of the student
g is the acceleration of gravity
In this problem, we have:
m = 30 kg is the mass of the student
is the acceleration of gravity, where the negative sign means the direction is downward
Substituting, we find the force of gravity on the student:
And since this is the only force acting on the student, it is also the net force on him.
Learn more about gravitational force:
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Answer:
It is directed inward, toward the center of a circle.