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3 years ago

9

Susan was traveling in an airplane. She looked out of a window in the airplane and saw clouds in the sky. Why could Susan see cl

ouds through the window of the airplane?
A.
Most of the light hitting the window was transmitted when it passed through the window.
B.
Most of the light hitting the window was reflected off of the window instead of passing through it.
C.
Most of the light hitting the window was refracted when it passed through the window.
D.
Most of the light hitting the window was absorbed by the window instead of passing through it.

1 answer:

lutik1710 [3]3 years ago

8 0

The correct answer Is C

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Where c is the speed of light, $\lambda$ is the wavelength and $\nu$ is the frequency.

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave.

<em>a). 100.2 MHz (typical frequency for FM radio broadcasting)</em>

Then, $\lambda$ can be isolated from equation 1:

$\lambda = \frac{c}{\nu}$ (2)

since the value of c is $3x10^{8}m/s$ . It is necessary to express the frequency in units of hertz.

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But $1Hz = s^{-1}$

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<em> </em>

$\nu = 1070kHz . \frac{1000Hz}{1kHz}$ ⇒ $1070000Hz$

But $1Hz = s^{-1}$

$\nu = 1070000s^{-1}$

Finally, equation 2 can be used:

$\lambda = \frac{3x10^{8}m/s}{1070000s^{-1}}$

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