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katen-ka-za [31]
4 years ago
5

I need a short written description of Newton's three laws.

Physics
1 answer:
Tom [10]4 years ago
6 0
Newton’s first law of motion, also called the law on inertia, states that an object continues in its state of rest or of uniform motion unless compelled to change that state by an external force.Newton’s second law of motion states that if a net force acts on an object, it will cause an acceleration of that object.Newton’s third law of motion<span> states that for every action there is an equal and opposite reaction. hope this wasnt two long!</span> 
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A beam of light strikes a mirror at angle of 23° to the normal. What is the angle between the incident and reflected beam?
My name is Ann [436]

Answer:

well, during reflection

angle of incident is equal to angle of reflection so if angles of incident is 23° , then angle of reflection is also equal to 23° .

so the total angle between the reflected and incident ray will be equal to angle of incidence plus angle of reflection

i.e. angle i + angle r = 23° + 23° = 46°

hence the required angle is 46°

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em> </em><em>.</em>

4 0
3 years ago
In forced convection, the fluid is forced to move by external means such as a fan, pump, or the wind. You must provide an answer
Grace [21]

Answer:

True

Explanation:

Convection simply means the transfer of heat resulting from the movement of the molecules of fluid, which can be liquid or gas.

Convection can either be natural or forced. natural convection occurs by a natural means ,such as the difference in density of warm air and cool air. This occurs when the cooler air falls and the warmer air rises.

However in forced convection, the fluid is agitated by an external force eg a fan or pump.

4 0
3 years ago
An 18 gauge copper wire (the size usually used for lamp cords), with a diameter of 1.02 mm,1.02 mm, carries a constant current o
larisa86 [58]

Answer:

J = 2.044x10⁶ A/m²

v = 1.50x10⁻⁴ m/s

Explanation:  

The current density (J) of the copper wire is giving by:  

J = \frac {I}{A}

<em>where I: electric current and A: cross-sectional area of the copper wire</em>

<u>The cross-sectional area of the copper wire can be calculated by:</u>

A = \frac {\pi d^{2}}{4} = \frac {\pi (1.02 \cdot 10^{-3} m)^{2}}{4} = 8.17 \cdot 10^{-07} m^{2}         

<u>Substituting the calculated area in the equation (1) we have:</u>

J = \frac {1.67 A}{8.17 \cdot 10^{-7} m^{2}} = 2.044 \cdot 10^{6} \frac {A}{m^{2}}    

Hence, the current density is 2.044x10⁶ A/m².    

To find the drift speed (v), we need to use the next equation:

v = \frac {J}{n q}  

<em>where n: the free-electron density, q: module of the charge of the electron </em>

v = \frac {2.044 \cdot 10^{6} \frac {A}{m^{2}}}{(8.5 \cdot 10^{28} {m^{-3}}) (1.6 \cdot 10^{-19} C)}  

v = 1.50 \cdot 10^{-04} \frac {m}{s}                            

So, the drift speed is 1.50x10⁻⁴ m/s.

Have a nice day!    

4 0
4 years ago
Read 2 more answers
А masd<br>Of 500kg a raised to a height of 6m In 30s<br>Find (a) Workdone .​
Mazyrski [523]

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

5 0
3 years ago
WORTH 10 POINTS! I WILL GIVE BRAINLIEST!
Sav [38]

Answer:

The Sun’s magnetic field, solar winds and the Earth's magnetic tail are responsible for making the aurora lights in the north and south poles look different, say international scientists. Researching the interactions of these phenomena have debunked previous theories around why the lights can have different shapes and can occur in different locations. This research also helps scientists to better understand the interactions between the sun and earth, which could help with predicting space weather.

<h2>hope it helps!</h2>

5 0
3 years ago
Read 2 more answers
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