The freezing point would be 3.72 *C
The molality of a solution containing 3. 0 moles of NaCl and 100. 0 moles of water is 30 mol/kg.
The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality. Mole per kilogram of solvent is the SI unit for molality.
Given:
3.0 moles of NaCl in 100 moles of water.
To find:
The molality of the solution
The moles of solute (NaCl) = 3.0 moles
The mass of solvent (water) = 100 moles (0.1 kg/mol)
Molality of a solution = Number of Moles of solute/ Mass of solvent(kg)
= 3.0 moles/0.1 kg/mol
= 30 mol/kg
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Answer:
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Explanation:
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Calcium oxide CaO = 40+16 = 56
Calcium hydroxide Ca(OH)_2 = 40+16+16+1+1 = 74
The ratio 56:74 is equal to 14:x with x being the unknown mass.
56/14 = 4
74/4 = 18.5
So the answer is 18.5g assuming the water is in excess
Explanation:
Iron atom is been oxidised as it losses 2 electron to form 2 + ion.