All categories

3 years ago

Solve each equation and match the solution

Mathematics

2 answers:

8_murik_8 [283]3 years ago

7 0

Answer:

Step-by-step explanation:

sub to yfbg jay

BartSMP [9]3 years ago

7 0

Answer:

b=3.4 so it is d

Step-by-step explanation:

Subtract 2.3 from both sides of the equation

b+2.3 = 5.7

b+2.3 - 2.3 = 5.7- 2.3

and the simply

You might be interested in

What is 96 divided by 1.5

Mamont248 [21]

64

-------------------------------

3 0

3 years ago

Read 2 more answers

The chickens on a certain farm consumed 600 pounds of feed in half a year. During that time the total number of eggs laid was 5,

raketka [301]

600*1,25$=750$
$\frac{750}{5000}=\frac{3}{20}=0,15$

8 0

3 years ago

Read 2 more answers

KL = 4x +3. JK = 4x + 2, and JL = 45 Find KL.

lbvjy [14]

Answer:

$KL=23$

Step-by-step explanation:

We are given the length of the whole line and its two halves. Since JK and KL make up the line JL, adding them together would make the line JL.

$(4x+3)+(4x+2) = 45$

$8x+5=45$

$8x=40$

$x=5$

Now we can plug the value of $x$ back into the expression we were given for the line KL.

$4(5)+3$

$23$

7 0

3 years ago

35 miles by 7 miles find the area for the triangle

SCORPION-xisa [38]

Answer:

35 x 7 = 245

Step-by-step explanation:

8 0

3 years ago

In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa

marissa [1.9K]

Answer:

The 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The confidence interval of the mean is given by the next formula:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$ [1]

We already know (according to the U.S. Department of Justice):

The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years ( $\\ \sigma = 9.6$ years).
The number of observations for the sample taken is $\\ n = 32$ .
The sample mean, $\\ \overline{x} = 38.9$ years.

For $\\ z_{1-\frac{\alpha}{2}}$ , we have that $\\ \alpha = 0.05$ . That is, the level of significance $\\ \alpha$ is 1 - 0.95 = 0.05. In this case, then, we have that the z-score corresponding to this case is:

$\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}$

Consulting a cumulative standard normal table, available on the Internet or in Statistics books, to find the z-score associated to the probability of, $\\ P(z$ , we have that $\\ z = 1.96$ .

Notice that we supposed that the sample is from a population that follows a normal distribution. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, $\\ \mu$ , and standard deviation, $\\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}$ .

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

That is, we have:

$\\ \overline{x} = 38.9$ years.

$\\ z_{1-\frac{\alpha}{2}} = 1.96$

$\\ \sigma = 9.6$ years.

$\\ n = 32$

Then

$\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}$

$\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}$

$\\ 38.9 \pm 1.96*1.697056$

$\\ 38.9 \pm 3.326229$

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

$\\ 38.9 + 3.326229$

$\\ 42.226229 \approx 42.23$ years.

Lower limit:

$\\ 38.9 - 3.326229$

$\\ 35.573771 \approx 35.57$ years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0

4 years ago