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luda_lava [24]
3 years ago
7

Which is greater: 5/8 or 0.65?

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
5 0

Answer:

To answer this you would have to turn the fraction into a decimal so divide 5 by 8.

vredina [299]3 years ago
3 0

Answer:

5/8 = 0.625 thus 0.65 is greater

Step-by-step explanation:

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And animals weight change from 12 pounds to 16 pounds what was the percent increase to the nearest whole number
amm1812
That's a 33% increase.

I calculated this using the formula:

\frac{|n-o|}{o} * 100

Where n = the new value (16 in your question), o = the old value (12 in your question) and the result is outputted as a percent increase.  You can check that this is correct by finding 33% of 12, adding the result to 12, and checking that the result equals your "new" number.  

Note that 33% is only an approximation as your question requires a number rounded to the nearest whole.


5 0
3 years ago
Find the following integral
ololo11 [35]

There's nothing preventing us from computing one integral at a time:

\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2

\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2

\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx

Expand the integrand completely:

x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x

Then

\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}

4 0
2 years ago
4(v – 6) + 5 = 4v - 19
erik [133]

Answer:

0

Step-by-step explanation:

is it helpful or not,?

8 0
3 years ago
When she just turned 22, Rae purchased 145 shares of Stock A for $25 per share; 87 shares of Stock B for $38 per share; 46 share
Damm [24]

Answer:

170

Step-by-step explanation:

you have to divide

8 0
3 years ago
Find the value of y such that the distance between the given points is indicated..... (5,y) and (8,-1) is 5.
maw [93]
(5,y)(8,-1)
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((8 - 5)^2 + (-1 - y)^2)
d = sqrt (3^2 + (-1 - 3)^2
d = sqrt (9 + (-4^2)
d = sqrt (9 + 16)
d = sqrt 25
d = 5

so ur points are : (5,-3)(8,-1)
6 0
3 years ago
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