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denis-greek [22]
2 years ago
11

No links please. Fill in the blanks. 67ns=[?]x10^[?]s

Mathematics
1 answer:
cluponka [151]2 years ago
7 0

Using scientific notation, it is found that:

67 ns = 6.7 \times 10^{-8}s

<h3>What is scientific notation?</h3>

A number in scientific notation is given by:

a \times 10^b

With the base being a \in [1, 10).

In this problem, the amount is of 67 ns.

Each ns has 10^{-9} seconds, hence:

67ns = 67 \times 10^{-9}s

We want the base between 1 and 10(exclusive), hence, we move the decimal digit one digit to the left and add one to the exponent, and the representation is:

67 ns = 6.7 \times 10^{-8}s

You can learn more about scientific notation at brainly.com/question/16394306

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Complete the equation of the line through (-10,-7)and-5,-9)<br> Y=
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4 years ago
A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
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Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

Multiply both sides by 20

20 * tan50 = \frac{OT}{20} * 20

20 * tan50 = OT

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Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

OP = 11.548

PT = OT - OP

PT = 23.836 - 11.548

PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

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