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Ganezh [65]
2 years ago
10

Last year at a certain high school, there were 124 boys on the honor roll and 125 girls on the honor roll. This year, the number

of boys on the honor roll decreased by 25% and the number of girls on the honor roll decreased by 20%. By what percentage did the total number of students on the honor roll decrease? Round your answer to the nearest tenth (if necessary).​
Mathematics
1 answer:
Darya [45]2 years ago
6 0

Answer:

23

Step-by-step explanation:

if 23 doesn't work try 2.8

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Keiko, Chang, and Abdul sent a total of 109 text messages over their cell phones during the weekend. Keiko sent 7 fewer messages
lbvjy [14]

9514 1404 393

Answer:

  • Keiko: 17
  • Chang: 24
  • Abdul: 68

Step-by-step explanation:

Let c represent the number of messages sent by Chang. Then Keiko sent (c-7) messages, and Abdul sent 4(c-7) messages. The total number sent was ...

  c + (c -7) +4(c -7) = 109

  6c -35 = 109 . . . . . . . . . . simplify

  6c = 144 . . . . . . . . . . . add 35

  c = 24 . . . . . . . . . . . divide by 6

  c-7 = 17

  4(c-7) = 68

Keiko sent 17, Chang sent 24, and Abdul sent 68 text messages.

5 0
3 years ago
Write each power as a product of the same factor. Then find the value. 7^2
Anvisha [2.4K]

Answer:

49

Step-by-step explanation:

7^2=49

3 0
3 years ago
A local grocery store chain has a sushi stand. That sushi stand makes samples for store customers to entice customers to purchas
Liula [17]

Answer: 0.99822

Step-by-step explanation:

Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.

So converting 14 into minutes will give  \frac{14}{60}=0.233

Let X=inter-arrival time between two customers

and here \lambda = 0.233

Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)

Now the Poisson distribution has PDF = \frac{\exp ^{-\lambda }\times \lambda ^{X}}{X!}

So P(X = 0) = \frac{\exp ^{-0.233}\times 0.233^{0}}{0!} = 0.79215

P(X= 1) = \frac{\exp ^{-0.233}\times 0.233^{1}}{1!} = 0.18457

P(X=2) = \frac{\exp ^{-0.233}\times 0.233^{2}}{2!} = 0.02150

Now adding all three probability gives =  0.79215 +0.18457 + 0.02150=0.99822

3 0
3 years ago
Finding Derivatives Implicity In Exercise, find dy/dx implicity.<br> 4x3 + ln y2 + 2y = 2x
lisov135 [29]

Answer:

\frac{dy}{dx}=\frac{y(1-6x^2)}{(1+y)}

Step-by-step explanation:

Given function : 4x³ + ln(y²) + 2y = 2x

on differentiating both sides with respect to 'x', we get

\frac{d(4x^3 + ln(y^2) + 2y)}{dx}= \frac{d(2x)}{dx}

or

12x^2+\frac{2}{y}(\frac{dy}{dx})+2(\frac{dy}{dx})=2

or

12x^2+(\frac{2}{y}+2)\frac{dy}{dx}=2

or

(\frac{2+2y}{y})\frac{dy}{dx}=2-12x^2

or

\frac{dy}{dx}=\frac{y(2-12x^2)}{2+2y}

or

\frac{dy}{dx}=\frac{2y(1-6x^2)}{2(1+y)}

or

\frac{dy}{dx}=\frac{y(1-6x^2)}{(1+y)}

3 0
3 years ago
Please tell me the answer and HOW you got them.
Maksim231197 [3]
You divide each cost to the package for A. to find the better price


4 0
3 years ago
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