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DerKrebs [107]
3 years ago
7

If the theoretical yield of a reaction is 0.132 g and the actual yield is 0.131 g , what is the percent yield?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
6 0
I believe the percent yield is 99.24%.
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A 1.25g sample of dry ice is added to a 765mL flask containing nitrogen gas at a temperature of 25.0°C and a pressure of 725 mmH
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Answer : The total pressure in the flask is 1.86 atm.

Explanation :

First we have to calculate the pressure of CO_2 gas.

Using ideal gas equation :

PV=nRT\\\\P_{CO_2}=\frac{w}{M}\frac{RT}{V}

where,

P = Pressure of CO_2 gas = ?

V = Volume of CO_2 gas = 765 mL = 0.765 L     (1 L = 1000 mL)

n = number of moles

w = mass of CO_2 gas = 1.25 g

M = molar mass of CO_2 gas = 44 g/mol

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of CO_2 gas = 25.0^oC=273+25.0=298K

Putting values in above equation, we get:

P_{CO_2}=\frac{w}{M}\frac{RT}{V}

P_{CO_2}=\frac{1.25g}{44g/mol}\frac{(0.0821L.atm/mol.K)\times 298K}{0.765L}=0.909atm

Now we have to calculate the total pressure in the flask.

P_T=P_{N_2}+P_{CO_2}

Given :

P_{CO_2}=0.909atm

P_{N_2}=725mmHg=\frac{725}{760}=0.954atm

conversion used : (1 atm = 760 mmHg)

Now put all the given values in the above expression, we get:

P_T=0.954atm+0.909atm=1.86atm

Therefore, the total pressure in the flask is 1.86 atm.

5 0
3 years ago
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