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patriot [66]
2 years ago
9

Complete the equation C14H30 = ________ + C7H14

Chemistry
1 answer:
Gemiola [76]2 years ago
3 0

Answer:

C14H30 -----> C7H14 + C2H4 +C5H10

Explanation:

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Rate is related to?<br> A. Volume<br> B. Time<br> C. Distance <br> D. Percentage
Inga [223]
I would say B. Time 
hope this helps:)
6 0
3 years ago
Read 2 more answers
13. What is a chemical equation?
s2008m [1.1K]

chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities on the right-hand side with a plus sign between the entities in both the reactants and the products and an arrow that points towards the products, and shows the direction of the reaction.[1] The coefficients next to the symbols and formulae of entities are the absolute values of the stoichiometric numbers.

Explanation:

<h3>CARRYINGTOLEARN:)</h3>

6 0
2 years ago
Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i
kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy

As can be seen from the reaction stoichiometry that:

<u>6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.</u>

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles of carbon dioxide are:

moles_{CO_2} = \frac{120 g}{44 g/mol}

moles_{CO_2} = 2.7273 mol

As mentioned:

<u>6 moles of carbon dioxide</u> gas can be produced from <u>1 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>1 mole of carbon dioxide</u> gas can be produced from <u>1/6 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>2.7273 mole of carbon dioxide</u> gas can be produced from <u>\frac{1}{6} \times 2.7273 moles of oxygen gas</u> in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass\ of\ oxygen\ gas = Moles \times Molar mass}

Mass\ of\ oxygen\ gas = 0.4545 \times 32}

Mass\ of\ oxygen\ gas = 14.544 g

<u>14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.</u>

3 0
3 years ago
Read 2 more answers
Binary molecules have
Alborosie

Answer:

C

Explanation:

It is formed as a result of a reaction between two non-metals

8 0
2 years ago
At a particular temperature and [A]0 = 2.00 x 10-2 Molar, concentration versus time data were collected for this reaction and a
madreJ [45]
<h2>Answer:kllk<em>klkkkk</em></h2>

Explanation:

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