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Ulleksa [173]
3 years ago
10

A recipe calls for chocolate chips in a ratio of 1 cup of white chocolate chips to 2 cups of milk chocolate chips. How many milk

chocolate chips were added if there were 6 cups of chocolate chips total?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

Answer:

4 cups of milk chocolate

Step-by-step explanation:

if there are 6 cups in total, then you can see that 1:2 is equal to 3 cups in total. If you multiply both sides of the ratio by 2, then you get 2:4, which is 6. You have to add the chocolate together to find how much it equals in total. Because it's white chocolate to milk chocolate, that would be 2:4, so there are 4 cups of milk chocolate.

Olin [163]3 years ago
6 0

Answer:

4

Explanation:

There are two basic ways to solve this problem.

(1) There are 2 cups of milk chocolate chips for every 3 cups of total chips. The total amount of chips added is 6, which is twice the amount that the ratio adds up to. So we double the amount of milk chocolate chips used in the ratio.

(2) For every 3 cups of total chocolate chips, there are 2 cups milk chocolate chips. Two is 2/3 of three, which means all you have to do is find 2/3 of 6 (the total amount of chocolate chips added). 2/3 of six is 4.

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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%E2%88%923x2%E2%88%9211x%2B7" id="TexFormula1" title="f(x) = &minus;3x2&minus
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x=   \frac{ - 11 +  \sqrt{205} }{6}  \:  \:  \:  \:  \: or \:  \:  \:  \:  \\x  =  \frac{ - 11 -  \sqrt{205} }{6}

Step-by-step explanation:

- 3x {}^{2}  - 11x + 7 = 0 \\ 3x {}^{2}  + 11x - 7 = 0

here,

a = 3 \\ b = 11 \\ c =  - 7

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D = b {}^{2}  - 4ac \\  = (11) {}^{2}  - 4(3)( - 7) \\  = 121 + 84 \\  = 205  > 0 \\

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