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Kryger [21]
2 years ago
7

(GIVING 20 POINTS) DUE TODAY PLZ HELPplz answer the questions below

Mathematics
2 answers:
Schach [20]2 years ago
6 0
1) 2 x 7 x 2 = 28
28 + (3 x 7 x 5) = 54 cm cubed
Hoochie [10]2 years ago
5 0
Was abt to answer but it’s already due now, srry
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Write an equation in slope-intercept form for the line that passes through (0, 1) and (2, 5)
denis-greek [22]

y = 2x + 1

.................

6 0
3 years ago
PLEASE HELP me!!! can give brainliest!
salantis [7]

Answer:

9 years ( approximately)

Step-by-step explanation:

900(1.03)^t = 1200

(1.03)^t= 1.33

( 1.03)^t= ( 1.03)^9

So, t= 9

5 0
3 years ago
50 POINTS
Marina86 [1]

vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.

Givens

vi = 160 ft/s

vf = 0 (the rocket stops at the maximum height.)

a = - 9.81 m/s

t = ????

Remark

YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.

Equation

a = (vf - vi)/t

Solve

- 32 = (0 - 160)/t Multiply both sides by t

-32 * t = - 160 Divide by -32

t = - 160/-32

t = 5

You will also need to solve for the height to answer part B

t = 5

vi = 160 m/s

a = - 32

d = ???

d = vi*t + 1/2 a t^2

d = 160*5 + 1/2 * - 32 * 5^2

d = 800 - 400

d = 400 feet

Part B

You are at the maximum height. vi is 0 this time because you are starting to descend.

vi = 0

a = 32 m/s^2

d = 400 feet

t = ??

formula

d = vi*t + 1/2 a t^2

400 = 0 + 1/2 * 32 * t^2

400 = 16 * t^2

400/16 = t^2

t^2 = 25

t = 5 sec

The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.

6 0
3 years ago
Find the common difference of the arithmetic sequence.
slavikrds [6]
Each time you are subtracting 1/9 to get the next term

For example, going from term 2 to term 3 is a difference of -1/9

(1 8/9) - (1/9) = 1 7/9

which is why the answer is choice A
7 0
3 years ago
What is an equation of the line that passes through the points ( 0,-7) and ( 5, -1)
tresset_1 [31]

Answer:

y = 5/6x - 5.167

Or

y = 5/6x - 31/6

Step-by-step explanation:

The equation of a line

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given points

( 0 , -7) ( 5 , -1)

x1 = 0

y1 = -7

x2 = 5

y2 = -1

Insert the values into the equation

m = -1 - (-7) / 5 - 0

m = -1 + 7 / 5

m = 6/5

y = 6/5x + c

Step 2: sub any of the two points given into the equation

y = 5/6x + c

( 5 , -1)

x = 5

y = -1

-1 = 5/6(5) + c

-1 = 5*5/6 + c

-1 = 25/6 + c.

c = -1 - 25/6

LCM = 6

c = -6 - 25 / 6

c = -31/6

c = -5.167

Step 3: sub c into the equation

y = 5/6x + c

y = 5/6x - 31/6

Or

y = 5/6x - 5.167

The equation of the line is

y = 5/6x - 5.167

7 0
2 years ago
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