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Olin [163]
3 years ago
5

-6(2r + 8) = -10(r - 3)

Mathematics
2 answers:
GaryK [48]3 years ago
7 0

Answer:

r=-39

Step-by-step explanation:

-6(2r + 8)= -10(r-3)    solve -6(2r+8)

-12r-48= -10(r-3)       solve -10(r-3)

-12r-48= 10r+30

+48            +48

-12r=-10r+78

+10r      +10r

-2r=78

-2r/-2=78/-2

r=-39

lys-0071 [83]3 years ago
6 0

Hey there!


-6(2r + 8) = -10(r - 3)

-6(2r) - 6(8) = -10(r) - 10(-3)

-12r - 48 = -10r + 30


ADD 10r to BOTH SIDES

-12r - 48 + 10r = -10r + 30 + 10r


SIMPLIFY IT!


-2r - 48 = 30


ADD 48 to BOTH SIDES

-2r - 48 + 48 = 30 + 48


SIMPLIFY IT!


-2r = 78


DIVIDE -2 to BOTH SIDES

-2r/-2 = 78/-2


SIMPLIFY IT!

r = -39


Therefore, your answer is: r = -39


Good luck on your assignment & enjoy day!


~Amphitrite1040:)

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Answer:

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Step-by-step explanation:

Solution:-

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                                 105 ± 12 units

- Process is producing this product at a 6-sigma quality standards i.e ( process is producing this product has a standard deviation (σ) of three units.)

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- The process capability (Cpu) is defined based on the Upper Specification Limit of the process (USL):

                             Cpu = (USL - u) / 3σ

- The process capability (Cpl) is defined based on the Lower Specification Limit of the process (LSL):

                             Cpl = ( u - LSL) / 3σ

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Where the specification limits are defined as:

                             LSL = u - SE = 105 - 12

                             LSL = 93 units

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                           Cpu = (USL - u) / 3σ

                           Cpu = (117 - 105) / 3σ

                           Cpu = 4 / σ

                           Cpl = ( u - LSL) / 3σ

                           Cpl = ( 105 - 99 ) / 3σ

                          Cpl = 4 / σ    

- The minimum of Cpu and Cpl is denoted as the Cpk value:

                           Cpk = min ( Cpu , Cpl )

                           Cpk = Cpu = Cpl = 4 / 8.36

                           Cpk = Cpu = Cpl = 4 / 8.36 = 0.4785          

               

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