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3 years ago

Step by step what is the answer to 11=12-q

Mathematics

1 answer:

Shtirlitz [24]3 years ago

7 0

Your answer: q=1.

Steps:

1.) Add q to both sides. (11 + q = 12 - q + q.)

2.) Simplify. (11 + q = 12.)

3.) Subtract 11 from both sides. (11 + q - 11 = 12 - 11.)

4.) Simplify again. (q = 1.)

Hope this helped :)

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7=4+1.5x

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3 years ago

Mcd de 120 , 160 , 180 , 200 paso por paso (el que responda le doy corona)

olga55 [171]

Answer:

The Highest Common Factor is 20

Step-by-step explanation:

Aquí le mostraremos paso a paso como hallar el Máximo Común Divisor de 120 y 180. (mcd de 120 y 180) Paso 1: Creamos una lista de todos los divisores de 120, que incluye 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, y 120. Paso 2: Siguiente, creamos una lista de todos los divisores de 180, que incluye 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, y 180. Paso 3: Finalmente, comparamos las listas de Paso 1 y Paso 2 y hallamos que el mayor número que tienen en común es 60. Esto significa que el Máximo Común Divisor de 120 y 180 es 60. MCD de 120 y 180 = 60

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2 years ago

Which operation should be done first to find the value of the expression: 18 + 5 x 42 = 2

Neko [114]

Answer:

Multiplication

Step-by-step explanation:

P = Parentheses

E = Exponents

M/D = Multiplication/Division

A/S = Addition/Subtraction

If you have both multiplication/division or addition/subtraction left, ALWAYS work left to right.

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2 years ago

Read 2 more answers

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marysya [2.9K]

Answer:

11/12

Step-by-step explanation:

Calculate the sum

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2 years ago

Simplify each exponential expression using the properties of exponents and match it to the correct answer.

saveliy_v [14]

1) (2 $\times$ 3^-2)^3 (5 $\times$ 3^2)^2 / (3^-2)(5 $\times$ 2)^2 = 2

2) (3^3) (4^0)^2 (3 $\times$ 2)^-3 (2^2) = 1/2

3) (3^7 $\times$ 4^7) (2 $\times$ 5)^-3 (5)^2 / (12^7) (5^-1) (2^-4) = 2

4) (2.3)^-1 (2^0) / (2.3)^-1 = 1

<u>Step-by-step explanation</u>:

Step 1 :

(2 $\times$ 3^-2)^3 (5 $\times$ 3^2)^2 / (3^-2)(5 $\times$ 2)^2

⇒ (2^3) (3^-6) (5^2) (3^4) / (3^-2) (10^2)

⇒ (2.2^2.5^2) (3^-6.3^4) / (3^-2) (10^2)

⇒ (2)(10^2) (3^-2) / (3^-2) (10^2)

⇒ 2

Step 2 :

(3^3) (4^0)^2 (3 $\times$ 2)^-3 (2^2)

Any number with power 'zero' is 1.

⇒ (3^3) (1^2) (3^-3) (2^-3) (2^2)

⇒ (2^(-3+2))

⇒ 2^-1 = 1/2

Step 3 :

(3^7 $\times$ 4^7) (2 $\times$ 5)^-3 (5)^2 / (12^7) (5^-1) (2^-4)

⇒ (12^7) (2^-3) (5^-3) (5^2) / (12^7) (5^-1) (2^-4)

⇒ (2^-3) (5^(-3+2)) / (5^-1) (2^-4)

⇒ (2^-3) (5^-1) / (5^-1) (2^-4)

⇒ 1 / (2^-1)

⇒ 2

Step 4 :

(2.3)^-1 (2^0) / (2.3)^-1

⇒ (2^0)

⇒ Any number with power 'zero' is 1

⇒ 1

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3 years ago