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salantis [7]
2 years ago
7

rofit = 50" alt="c.p = rs.750 \: profit = 50" align="absmiddle" class="latex-formula">
find s.p from this case​
Mathematics
1 answer:
White raven [17]2 years ago
8 0

Answer:

SP=Rs 800

Step-by-step explanation:

→As we have,

→Profit=SP-CP

Now,

Profit=SP-CP\\Rs50=SP-Rs750\\Rs50+Rs750=SP\\SP=Rs800

You might be interested in
Find the proportion of observations from a standard Normal distribution that falls in each of the following regions. -2.31 <
Igoryamba
\mathbb P(-2.31
4 0
2 years ago
A shipping container will be used to transport several 100-kilogram crates across the country by rail. The greatest weight that
natulia [17]

Answer:

x ≤ 207 crates

Step-by-step explanation:

Greatest weight of the container = 27,500 kilograms

Weight of other shipment = 6,800 kilograms

Weight of a crate = 100 kilograms

Number of 100-kilogram crates that can be loaded into the shipping container = x

The inequality is

27,500 ≤ 6800 + 100x

27,500 - 6800 ≤ 100x

20,700 ≤ 100x

x ≤ 20,700 / 100

x ≤ 207 crates

3 0
3 years ago
The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A
Aloiza [94]

Answer:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

\mu=37 and \sigma=28  and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

4 0
3 years ago
Mike put sports books on 1/3 of his bookshelf. He put history books on 1/4 of the bookshelf . What fraction of the bookshelf did
Shkiper50 [21]

Answer:

66.67% or 2/3

Step-by-step explanation:

He put 1/3 of his sports books on the shelf. Ignore the 1/4 and focus on how much space the sports books are not taking up which would be 1-1/3=2/3 or 66.67%.

5 0
3 years ago
The regression equation below relates the scores students in an advanced statistics course received for homework completed and f
serg [7]

Answer: d.) None of the answer choices is correct

Step-by-step explanation:

The homework score is an independent variable (known) and on the x-axis, while the midterm exam is the dependent variable, so it's on the y-axis

y = 0.91x - 94.4; and x=420

Substitute x as 420 into the equation.

y = 382.2 - 94.4 = 287.8, or approximately 288.

And this value isn't in the options above.

7 0
3 years ago
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