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2 years ago

One half the difference of the cube of a number, x, and three

Mathematics

1 answer:

horsena [70]2 years ago

3 0

Answer:

(1/2)(x³ - 3)

Step-by-step explanation:

That would be (1/2)(x³ - 3).

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If Ac={vt2/r) and vt=2 and r=2 find Ac a. 4 b. 2 C. 1 D. 8

ankoles [38]

given: $Ac=\frac{vt2}r \quad vt=2 \quad r=2$

$\therefore Ac=\frac{(2)2}{2}=2$

5 0

2 years ago

Cookies are being sold in the cafeteria to raise money for the cheerleaders. One giant cookie costs $1 while each one bought aft

sladkih [1.3K]

Answer:

y = 0.75x + 1

Step-by-step explanation:

Here, we want to write an equation in slope-intercept form to represent this information

Since $1 is the cost of 1 only, this represents our y intercept

It means if we are not interested in purchasing more than 1, our cost will be $1

Now, for each one bought after, we have a rate of $0.75 per one

Mathematically, that will be $0.75 times the number bought after

Hence. we have that;

y = 0.75x + 1

if 1, x = 0; so we have cost of 1 as $1

7 0

2 years ago

30 POINTS NEED HELP ASAP WILL MARK BRAINLY

padilas [110]

Answer:

Step-by-step explanation:

the 3rd one

5 0

2 years ago

Write -7.32 as a Fraction/Mixed Number In Simplest Form. Also Show Steps To How You Got To Your Answer.

Mamont248 [21]

To write 7.32 as a fraction you have to write 7.32 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

7.32 = 7.32/1 = 73.2/10 = 732/100

And finally we have:

7.32 as a fraction equals 732/100

7 0

2 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$