Answer:
Hamburger Chicken
Adults 65 60 125
children 55 20 75
120 80 200
a)What is the probability that a randomly selected individual is an adult?
Total no. of adults = 125
Total no. of people 200
The probability that a randomly selected individual is an adult = 
b) What is the probability that a randomly selected individual is a child and prefers chicken?
No. of child prefers chicken = 20
The probability that a randomly selected individual is a child and prefers chicken= 
c)Given the person is a child, what is the probability that this child prefers a hamburger?
No. of children prefer hamburger = 55
No. of child = 75
The probability that this child prefers a hamburger= 
d) Assume we know that a person has ordered chicken, what is the probability that this individual is an adult?
No. of adults prefer chicken = 60
No. of total people like chicken = 80
A person has ordered chicken, the probability that this individual is an adult= 
Imma go with F just because I think it’s right
Answer: Yes
Step-by-step explanation: Calculator
3x+7=-x-1
move -x to the other side
sign changes from -x to +x
3x+x+7=-x+x-1
3x+x+7=-1
4x+7=-1
move 7 to the other side
sign changes from +7 to -7
4x+7-7=-1-7
4x=-8
Divide by 4 for both sides
4x/4=-8/4
Answer: x=-2
Let <em>u</em> = (1, 0) and <em>v</em> = (0, 1). Then
<em>T</em> (<em>u</em>) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)
<em>T</em> (<em>v</em>) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)
=> <em>T</em> (<em>u</em>) + <em>T</em> (<em>v</em>) = (-1, 9, 5)
but
<em>T</em> (<em>u</em> + <em>v</em>) = <em>T</em> (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)
=> <em>T</em> (<em>u</em> + <em>v</em>) ≠ <em>T</em> (<em>u</em>) + <em>T</em> (<em>v</em>)
which means <em>T</em> does not preserve addition, so it is not linear.